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3 years ago

11

Surface Area of a Triangular Pyramid, please help!

1 answer:

8090 [49]3 years ago

5 0

Answer:

surface area of the triangular pyramid

=(1/2×9×7.8)+(3×1/2×9×12.3)

=35.1+166.05

=201.15 inch²

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Instructions: Select the correct answer from the drop-down menu.

True [87]

Remember
(x^m)/(x^n)=x^(m-n)

7^16/6^12=7^(16-12)=6=7^4

so

7^4=7^-18/?
?=7^?

7^4=7^-18/7^?
7^-18/7^?=7^(-18-?)=7^4
-18-?=4
add 18
-?=22
tmes -1
?=-22
7^-22

answer is C

3 0

3 years ago

Read 2 more answers

If ABC Toys sold 25 “Little Drummer Boys” in June 2012 and ABC Toys has seen a 20% increase in sales of “Little Drummer Boys” ev

KIM [24]

You would want to order 44 of the toys.

25 x 120% = 30 (2013)
30 x 120% = 36 (2014)
36 x 120% = 43.2, you can have .2 of a toy so you round up to the next whole number. So 44 (2015)
Hope this helps! :D

7 0

3 years ago

Read 2 more answers

Rationalise 1/√5 please tell

Assoli18 [71]

Answer:

Step-by-step explanation:

1/ $\sqrt{5}$

=1 $\sqrt{5}$ * $\sqrt{5}$ / $\sqrt{5}$

=1* $\sqrt{5}$ / $\sqrt{5}$ * $\sqrt{5}$

=1 $\sqrt{5}$ /5

6 0

3 years ago

The tuition at a college increased from 50,000 in 2006 to to 59,000 in 2007. What is the percent increase in tuition

Paha777 [63]

Answer:

37%

Step-by-step explanation:

5 0

3 years ago

Suppose a box of Cracker Jacks contains one of 5 toy prizes: a small rubber ball, a whistle, a Captain America decoder ring, a r

lakkis [162]

Answer:

11.42 boxes

Step-by-step explanation:

For the first box bought, there is a 100% chance of getting a unique toy (since you still don't have any). E₁ = 1.

After that, there is a 4 in 5 chance of getting a unique toy from the next box, the expected number of boxes required is:

$E_2 = (\frac{4}{5})^{-1} = 1.25$

For the next unique toy, there is now a 3 in 5 chance of getting it:

$E_3 = (\frac{3}{5})^{-1} = 1.67$

Following that logic, there is a 2 in 5 chance of getting the 4th unique toy:

$E_4 = (\frac{2}{5})^{-1} = 2.5$

Finally, there is a 1 in 5 chance to get the last unique toy:

$E_5 = (\frac{1}{5})^{-1} = 5$

The expected number of boxes to obtain a full set is:

$E=E_1+E_2+E_3+E_4+E_5\\E=1+1.25+1.67+2.5+5\\E=11.42\ boxes$

5 0

3 years ago