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Ostrovityanka [42]

2 years ago

8

ABCD is a parallelogram with coordinates A(4, 2), B(3, −1), C(−1, −1), and D(−1, 2). To prove that ABCD is a parallelogram, you

would find which of the following?
A measures of the angles
B slopes of the diagonals
C lengths of the diagonals
D slopes of the sides

1 answer:

daser333 [38]2 years ago

3 0

The answer is A im pretty sure

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Determine the sum of the arithmetic series: 5+18 +31 +44 + ... 161.

Finger [1]

Answer:

1079

Step-by-step explanation:

Hello,

18-5 = 13

31-18=13

44-31=13

161=5+13*12

So we need to compute

$\displaystyle \sum_{k=0}^{k=12} \ {(5+13k)}\\\\=\sum_{k=0}^{k=12} \ {(5)} + 13\sum_{k=1}^{k=12} \ {(k)}\\\\=13*5+13*\dfrac{12*13}{2}\\\\=65+13*13*6\\\\=65+1014\\\\=1079$

Thanks

3 0

3 years ago

Work it out plzsssss help me

lakkis [162]

1. alternate interior angles
2. angle 1 ≈ angle 2
So,
2x+5=x+59
-x. -x
x+5=59
-5 -5
x=54!!

3. Plug in the value of x into the expression for angle 2
54+59=113
Angle 2=113°

5 0

2 years ago

During a 5-day work week, pete was sick for 2 days .what fraction of the work week was he sick?

timofeeve [1]

I think the answer is 2/5

6 0

2 years ago

Find the x- and y-intercept of the line. -7/5x -4y = 7 A. x -intercept is -7/4; y-intercept is 5 B. x -intercept is 5; y-interce

DochEvi [55]

Put y=0
-7/5x-0=7
x=7*-5/7=-5
x intercept=-5
put x=0
-0-4y=7
y=-7/4
y intercept =-7/4

4 0

2 years ago

If a circle has circumference c, what is it’s are in terms of C

Scilla [17]

$\text {Circumference = } 2 \pi r$

$c = 2 \pi r$

$\text {r = } \dfrac{c}{2 \pi }$

$\text {area = } \pi r^2$

Sub r into area:

$\text {area = } \pi ( \dfrac{c}{2 \pi } )^2$

$\text {area = } \dfrac{\pi c^2}{4 \pi^2 }$

$\text {area = } \dfrac{\ c^2}{4 \pi }$

7 0

2 years ago