A jar contains 8 marbles numbered 1 through 8. an experiment consists of randomly selecting a marble from the jar, observing the
number drawn, and then randomly selecting a card from a standard deck and observing the suit of the card (hearts, diamonds, clubs, or spades). how many outcomes are in the sample space for this experiment? how many outcomes are in the event "an even number is drawn?" how many outcomes are in the event "a number more than 2 is drawn and a red card is drawn?" how many outcomes are in the event "a number less than 3 is drawn or a club is not drawn?"
There are 8 possible outcomes for a marble being drawn and numbered. {1,2,3,4,5,6,7,8} There are 4 possible outcomes for a card being selected from a standard deck. { <span>hearts, diamonds, clubs, spades} So the number of outcomes in the sample space would be 8 x 4 = 32.
In the event "an even number is drawn", there are only 4 possible outcomes for a marble being drawn, {2,4,6,8}, whereas there are still 4 possible outcomes for a suit. So the number of outcomes in the event is 4 x 4 = 16.
</span><span>In the event "a number more than 2 is drawn and a red card is drawn", there are 6 possible outcomes for the marble being drawn, {3,4,5,6,7,8}, whereas there are only two possible suits for a card being selected as red, {heart, diamond}. So the number of outcomes in this event is 6 x 2 = 12.
In the event </span><span>"a number less than 3 is drawn or a club is not drawn", the number drawn could be 1 or 2 whereas a spade/heart/diamond could be selected. So the number of outcomes is 2 x 3 = 6.</span><span>
1. The domain of the function given in the problem are all those values for which the function that is in the denomiantor is different from zero, because the division by 0 is not allowed.
2. You can make the denominator equal to zero and solve it, as you can see below:
The law of cosines can be used to find the angle. The sides adjacent to that angle are a=34, b=38, and the side opposite is c=8. Then the angle is found from ...
c² = a² +b² -2ab·cos(C)
cos(C) = (a² +b² -c²)/(2ab)
C = arccos((a² +b² -c²)/(2ab))
C = arccos((34² +38² -8²)/(2·34·38)) = arccos(317/323)
C ≈ 11.06°
From the footballer's viewpoint, the goal posts are 11.06° apart.