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Irina18 [472]
3 years ago
11

Find M angle P The diagram is not a scale

Mathematics
1 answer:
coldgirl [10]3 years ago
8 0
106 + m∠p = 180

Subtract 106 from both sides. 

m∠p = 74°, the second option. 
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Solve the equation for y. 8y+35=3y
Luda [366]

Answer:

y = - 7

Step-by-step explanation:

Given

8y + 35 = 3y ( subtract 3y from both sides )

5y + 35 = 0 ( subtract 35 from both sides )

5y = - 35 ( divide both sides by 5 )

y = - 7

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4 years ago
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Monica [59]

Answer:

right angle i think

Step-by-step explanation:

3 0
3 years ago
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Yuri [45]

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3 years ago
A cosine function has a period of 4, a maximum value of 20, and a minimum value of 0. The function is a not a reflection of its
3241004551 [841]

Answer:

Step-by-step explanation:

You'll need to find a way to share the graph or graphs associated with this problem.

The period is 4.  The relationship between period and b (the coefficient of the independent variable of the cosine function) is (period) =(2π.b).  Given that the period here is 4,

       2π                          2π

4 = ---------, and so b = ------- = π/2.

                                       4

So now our y  = a*cos (bx + c) becomes

                    π

y = 10*cos (------x + 0 + 10

                     2

The horizontal center line of this cosine curve is y = 10.  The maximum value of the curve is 20, which is 10 + 10, and the minimum value is 0, which is 10 - 10.

                           

5 0
3 years ago
A maintenance manager must test a new repair method that should increase the expected time between repairs. For each machine use
Murljashka [212]

Answer:

a) The value t=1.73 < 1.833 fall in the acceptance region, so the effect is not significant. The null hypothesis can not be rejected.

The claim that the new method is better doesn't have enough statistical evidence.

b) P-value=0.06

c) 95% CI

-25 \leq\mu_n-\mu_c\leq  189

Step-by-step explanation:

A) We have to test the hypothesis about the difference of the means.

The claim is that the new method gives larger times between repairs.

1) State the null and alternative hypothesis

H_0: \mu_n\leq\mu_c\\\\H_a: \mu_n>\mu_c

The significance level is 0.05.

2) The sample mean and standard deviation of the current method is

M_c=254\\\\ s_c=113

The sample mean and standard deviation of the new method is

M_n=336\\\\ s_n=99

The difference of means is

M_d=M_n-M_c=336-254=82

The standard deviation of the difference of means can be estimated as:

s_d=\sqrt{\frac{s_n^2+s_c^2}{n} }=\sqrt{\frac{99^2+113^2}{10} }=\sqrt{2246}=47.4

3) Then, we can calculate the t-statistic as:

t=\frac{M_d-(\mu_n- \mu_c)}{s_d} =\frac{82-0}{47.4}=1.73

4) For 9 degrees of freedom and a significance level of 0.05, the critical value for t is t=1.833.

5) The value t=1.73 < 1.833 fall in the acceptance region, so the effect is not significant. The null hypothesis can not be rejected.

The claim that the new method is better doesn't have enough statistical evidence.

B) For a df=10-1=9 and t=1.73, the P-value is

P(t_9>1.73)=0.06

C) In this case, for 9 degrees of freedom and 95% CI, the critical value of t is t=2.262.

The CI can be written as:

M_d-t*s_d\leq\mu_n-\mu_c\leqM_d+t*s_d\\\\82-2.262*47.4\leq\mu_n-\mu_c\leq 82+2.262*47.4\\\\82-107\leq\mu_n-\mu_c\leq 82+107\\\\-25 \leq\mu_n-\mu_c\leq  189

7 0
3 years ago
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