We know that
<span>The measure of the interior angle is the half-summit of the arcs that comprise it and its opposite.
see the attached figure with letters to better understand the problem
measure of the arc ADCB is equal to 180 degrees
arc DC=180-(arc BC+arc AD)----> arc DC=180-(60+70)---> 50</span>°
<span>arc DC=50</span>°
<span>so
</span>∡x=(1/2)*[arc AB+arc DC]---> (1/2)*[180+50]----> ∡ x=115°
<span>
the answer is
x=115</span>°
<span>The measure of the interior angle is the half-summit of the arcs that comprise it and its opposite.
see the attached figure with letters to better understand the problem
measure of the arc ADCB is equal to 180 degrees
arc DC=180-(arc BC+arc AD)----> arc DC=180-(60+70)---> 50</span>°
<span>arc DC=50</span>°
<span>so
</span>∡x=(1/2)*[arc AB+arc DC]---> (1/2)*[180+50]----> ∡ x=115°
<span>
the answer is
x=115</span>°