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2 years ago

Identify the scale factor from A to B

Mathematics

1 answer:

Tomtit [17]2 years ago

6 0

The answer is 3. You divide the numbers in the bigger triangle by the numbers on the smaller one to find the scale factor

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5² x 5³ = Choices: 5 55 5^5 5^6

Vesna [10]

Answer:

5^5

Step-by-step explanation:

when multiplying two expression like this you should add up their powers

in this case it's 2 + 3

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3 years ago

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Tom says that he needs 6 rolls to obtain each possible outcome on a 6-sided die. On the fourth roll, he rolls his second "3". To

Anna11 [10]

Answer:

Tom is incorrect

Step-by-step explanation:

The odds of getting any number on a 6-sided die are $1:6$

Every time he rolls, there is a $1:6$ chance he gets any number. Therefore, it is totally plausible to get the same number again. As the number of rolls tends toward infinity, the ratio of each number occurring to number of rolls equals $1:6$ .

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3 years ago

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Springboard Geometry Chapter 21 Mid-Unit Assessment

ExtremeBDS [4]

I really don't know just say its o

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3 years ago

If f(x)=(x-1)^1/3 then what is f^-1(x)

Stels [109]

Answer:

The answer is f−1(x)=1x13

Step-by-step explanation: hi

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3 years ago

A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to

melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

$P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}$

Mean of X:

$E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42$

Variance of X:

$E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}$

$var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58$

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3 years ago