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2 years ago

Craig used repeated addition to show 3 times 3/5. Which shows an expression Craig could write?

Mathematics

2 answers:

Vesnalui [34]2 years ago

6 0

$\frac{3}{5} + \frac{3}{5} + \frac{3}{5} = \frac{9}{5} = 1 \frac{4}{5} 
$

guapka [62]2 years ago

5 0

3/5+3/5+3/5=9/5=1 4/5

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The credit remaining on a phone card (in dollors) is a linear function of the total calling trime made with the card ( in minute

KATRIN_1 [288]

After 85 minutes of calls, there are $27.25 left on the card.

<h3>What is the remaining credit after 85 minutes of calls?</h3>

A linear equation in slope-intercept form is:

y = a*x + b

Where a is the slope.

If the line passes through two points (x₁, y₁) and (x₂, y₂) the slope is:

$a = \frac{y_2 - y_1}{x_2 - x_1}$

In this case, we know that the line passes through the points (22, 36.7) and (52, 32,20)

(points of the form (time, dollars)).

So the slope is:

$a = \frac{32.2 - 36.7}{52 -22} = -0.15$

The linear equation is then:

y = -0.15*x + b

To find the value of b, we use the point (22. 36.7)

36.7 = -0.15*22 + b

36.7 + 0.15*22 = b = 40

Then the linear equation is:

y = -0.15*x +40

The amount remaining in the credit card after 85 minutes is given by evaluating the above equation in x = 85.

y = -0.15*85 + 40 = 27.25

This means that after 85 minutes of calls, there are $27.25 left on the card.

If you want to learn more about linear equations:

brainly.com/question/1884491

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7 0

1 year ago

Can u solve this for me: 72 + 4x = 2x + 82 and please show work

8_murik_8 [283]

The answer is X = 5 because first you have to take away 2x from that side so u minus 2x from 4x that gives u: 72 + 2x = 82 then you have to minus 72 from both sides and that gives you 2x = 10 once you have that you divide both sides by 2 because you want the X by itself and once you get that X = 5. Hope this helped!

8 0

3 years ago

Read 2 more answers

Y''+y'+y=0, y(0)=1, y'(0)=0

mars1129 [50]

Answer:

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form $ay''+by'+cy=0$ .

Given: $y''+y'+y=0$

Let $y=e^{rt}$ be it's solution.

We get,

$\left ( r^2+r+1 \right )e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2+r+1=0$

{ we know that for equation $ax^2+bx+c=0$ , roots are of form $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ }

We get,

$y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}$

For two complex roots $r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta$ , the general solution is of form $y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )$

i.e $y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Applying conditions y(0)=1 on $e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$ , $c_1=1$

So, equation becomes $y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

On differentiating with respect to t, we get

$y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )$

Applying condition: y'(0)=0, we get $0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}$

Therefore,

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

3 0

2 years ago

What is the experimental probability that Dan will roll a number 3 the next time he rolls the number cube?

Bad White [126]

The experimental probability changes every time he rolls the die but if its just the next roll he has a 1/6 chance of getting a 3

4 0

2 years ago

A rectangular piece of sheet metal has a length that is 6 in. less than twice the width. a square piece 3 in. on a side is cut f

m_a_m_a [10]

The original width would be 19 and the original length would be 32.

Let w be the width. Then 2w-6 would be the length. However, after cutting a 3-inch square from each corner, both the width and length left over to fold into a box would be 6 inches smaller; thus the dimensions would be w-6 and 2w-6-6 or 2w-12.

Since the section cut out is 3 inches long, 3 will be the height of the box.

Volume is found by multiplying the length, width and height of the box; thus we have:

1014=(w-6)(2w-12)(3)

We multiply the binomials and have:
1014 = [w*2w-12*w-6*2w-6(-12)](3)
1014 = (2w²-12w-12w+72)(3)
1014 = (2w²-24w+72)(3)
1014 = 6w² - 72w + 216

When solving a quadratic equation, we want it set equal to 0. Subtract 1014 from each side:

1014-1014 = 6w² - 72w + 216 - 1014
0 = 6w² - 72w - 798

We will use the quadratic formula to solve this:

$w=\frac{-b\pm \sqrt{b^2-4ac}}{2a}
\\
\\=\frac{--72\pm \sqrt{(-72)^2-4(6)(-798)}}{2(6)}
\\
\\=\frac{72\pm \sqrt{5184--19152}}{12}
\\
\\=\frac{72\pm \sqrt{5184+19152}}{12}
\\
\\=\frac{72\pm \sqrt{24336}}{12}
\\
\\=\frac{72\pm 156}{12}
\\
\\=\frac{72+156}{12} \text{ or } \frac{72-156}{12}
\\
\\=\frac{228}{12} \text{ or } \frac{-84}{12}=19 \text{ or } -7$

Since we cannot have a negative number for a measurement, 19 has to be the width; then 2(19)-6 = 32 would be the length.

4 0

3 years ago