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Studentka2010 [4]
3 years ago
11

Where are chemicals found at work?

Chemistry
1 answer:
IgorLugansk [536]3 years ago
4 0
Only in cleaning products
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What would be the total volume of the new solution when it is changed from 0.2 M to 0.04 M?
34kurt
The question is incomplete.

You need two additional data:

1) the original volume
2) what solution you added to change the volume.

This is a molarity problem, so remember molarity definition and formula:

M = n / V in liters: number of moles per liter of solution

To give you the key to answer this kind of questions, supppose the original volumen was 1 ml and that you added only water (solvent).

The original solution was:

V= 1 ml
M = 0.2 M

Using the formula for molarity, M = n / V

n = M×V = 0.2 M × (1 / 10000)l = 0.0002 moles

For the final solution:

n = 0.0002 moles
M = 0.04

From M = n / V ⇒ V = n / M = 0.002 moles / 0.04 M = 0.05 l

Change to ml ⇒ 0.05 l × 1000 ml / l = 50 ml.  This would be the answer for the hypothetical problem that I assumed for you.

I hope this gives you all the cues you need to answer similar problems about molarity.
6 0
3 years ago
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How would you describe an electron
avanturin [10]

Answer:

an electron is part of the 3 things that are in an atom, it has a negative charge

8 0
4 years ago
How do you think the amount of a material affects its tendency to sink or float? <br> ASAP
Ksivusya [100]

Answer:

it dependes on the material

Explanation:

what is the material

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Hello there :3 Please anwser this Combined gas law problem for me . By the way just anwser #4 for me that’s all . I uploaded the
stellarik [79]

Answer:

136L

Explanation:

p1v1=p2v2

114 x44.0=37.0x V2

V2=136L

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If the mass of the products of a chemical reaction was 100 g, what was
Rzqust [24]
If the mass of all of the products in a chemical reaction is equal to 100g then the mass of the reactants in that same reaction had to have had a mass of 100g this is due to the law of conservation of matter stating matter cannot be created or destroyed in a chemical reaction.
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3 years ago
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