Where are chemicals found at work?

Under certain conditions the rate of this reaction is zero order in dinitrogen monoxide with a rate constant of ·0.0047Ms−1: 2N2

leva [86]

Answer:

250 mmol are left after 26.60 secs ≅ 26.6 seconds

Explanation:

zero order kinetics formula is:

[A] = [A₀] - kt

where [A] = amount left; [A₀] = amount remaining; k = rate constant; t = time

concentration [A₀] = mole/volume = 0.5 mole/2.0L = 0.25

[A] = 0.25 mole/2.0L = 0.125 M

k = 0.0047 Ms⁻¹

t = {[A]-[A₀]}/-k = (0.125 - 0.25)/(-0.0047) = 26.60 seconds = 26.6 seconds

the amount is reduced by half after 26.6 seconds

6 0

3 years ago

How many grams are in 2.6 moles of calcium

rjkz [21]

No.of moles=mass/Mr

2.6*40.1=mass

Mass= 104.16g

4 0

4 years ago

Balance the following redox reaction in basic solution. Cl â’ (aq) + MnO â’ 4 (aq) â†’ Cl 2 (g) + MnO 2 (s)

FinnZ [79.3K]

$6\; \text{Cl}^{-} \; (aq) + 2\; \text{MnO}_4^{-} \; (aq) + 4 \; \text{H}_2 \text{O} \; (l) \to 3\; \text{Cl}_2 \; (g) + 2\; \text{MnO}_2 \; (s) + 8\; \text{OH}^{-} \; (aq)$

<h3>Explanation</h3>

The oxidation state of the manganese atom $\text{Mn}$ changes from +7 as in $\text{MnO}_4^{-}$ to +4 as in $\text{MnO}_2$ .
There are one $\text{Mn}$ atom in each $\text{MnO}_4$ ion.
Reducing each $\text{MnO}_4^{-}$ ion would thus consume three electrons.

Similarly, the oxidation state of the chlorine atom $\text{Cl}$ changes from -1 as in $\text{Cl}^{-}$ to 0 as in $\text{Cl}_2$ .
It takes two $\text{Cl}^{-}$ ions to produce one $\text{Cl}_2$ molecule.
Oxidizing every two $\text{Cl}^{-}$ would thus produce one $\text{Cl}_2$ while releasing two electrons.

Three $\text{Cl}_2$ molecules contain six chlorine atoms. Three $\text{Cl}_2$ would thus correspond to six $\text{Cl}^{-}$ ions.

Combining six $\text{Cl}^{-}$ , two $\text{MnO}_4^{-}$ ions, three $\text{Cl}_2$ ions, and two $\text{MnO}_2$ would balance the changes in oxidation state.

$6\; \text{Cl}^{-} \; (aq) + 2\; \text{MnO}_4^{-} \; (aq) \to 3\; \text{Cl}_2 \; (g) + 2\; \text{MnO}_2 \; (s)$ (NOT BALANCED)

Still, the product side lacks four oxygen atoms.

In an acidic environment, oxygen atoms would combine with protons to produce water.
In a basic environment (like this one,) there are nearly no protons for oxygen atoms to combine with. Oxygen atoms will likely combine with water to produce hydroxide ions.

Each oxygen atom combine with a water molecule to produce two hydroxide ions. Adding four water molecules and eight hydroxide ions would balance the equation.

5 0

3 years ago

What is the Brønsted-Lowry base in this reaction: NH2−+CH3OH→NH3+CH3O−?(1 point)

Viefleur [7K]

The Brønsted-Lowry base in the given reaction is NH₂⁻. The correct option is the fourth option NH2−

To determine which is the Brønsted-Lowry base in the given reaction:

NH2−+CH3OH→NH3+CH3O−

First, we will write the equation for the reaction properly

The equation is:

NH₂⁻ + CH₃OH → NH₃ + CH₃O⁻

Now, to determine which among the species in the above reaction is the Brønsted-Lowry base, we will start by defining what a <em>Brønsted-Lowry base</em><em> </em>is.

A Brønsted-Lowry base is any species that is capable of accepting a proton, which requires a lone pair of electrons to bond to the H⁺.

In simple terms, a Brønsted-Lowry base is a proton acceptor.

In the above reaction, NH₂⁻ is the species that is capable of accepting a proton and it has a lone pair of electrons to bond to the H⁺.

∴ NH₂⁻ is the Brønsted-Lowry base in the reaction

Hence, the Brønsted-Lowry base in the given reaction is NH₂⁻. The correct option is the fourth option NH2−

Learn more here: brainly.com/question/13017688

7 0

3 years ago

Answer the following stoichiometry question:

labwork [276]

Answer:

Mass = 684.2 g

Explanation:

Given data:

Moles of Aluminium = 25.36 mol

Mass of Al = ?

Solution:

Formula:

Number of moles = mass/ molar mass

Mass = number of moles × molar mass

Molar mass of Aluminium = 27 g/mol

Now we will put the values:

Mass = 25.36 mol × 26.98 g/mol

Mass = 684.2 g

4 0

4 years ago