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3 years ago

How many grams of iron(II) chloride are needed to produce 44.3 g iron(II) phosphate in the presence of excess sodium phosphate?

Chemistry

1 answer:

zalisa [80]3 years ago

5 0

Answer:

47.2 g

Explanation:

Let's consider the following double displacement reaction.

3 FeCl₂ + 2 Na₃PO₄ → Fe₃(PO₄)₂ + 6 NaCl

The molar mass of Fe₃(PO₄)₂ is 357.48 g/mol. The moles corresponding to 44.3 g are:

44.3 g × (1 mol / 357.48 g) = 0.124 mol

The molar ratio of Fe₃(PO₄)₂ to FeCl₂ is 1:3. The moles of FeCl₂ are:

3 × 0.124 mol = 0.372 mol

The molar mass of FeCl₂ is 126.75 g/mol. The mass of FeCl₂ is:

0.372 mol × (126.75 g/mol) = 47.2 g

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erik [133]

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How many moles of methane occupy a volume of 2.00 l at 50.0°c and 0.500 atm answer?

Sauron [17]

Data Given:
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Volume = V = 2.0 L

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Solution:
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P V = n R T
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trapecia [35]

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djverab [1.8K]

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Vinil7 [7]

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