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3 years ago

What is the difference between a homogeneous and a heterogeneous mixture?

Chemistry

1 answer:

Ne4ueva [31]3 years ago

7 0

Answer and explanation :

DIFFERENCE BETWEEN HOMOGENEOUS AND HETEROGENEOUS MIXTURE :

In homogeneous mixture the component which are present in the mixture all are in the same proportion whereas in heterogeneous mixture the component which are present in the mixture don't have the same proportion
We can not pick out the component of homogeneous mixture but in heterogeneous mixture we can pick out the components from the mixture
Example of homogeneous mixture is water, oil ,water sugar solution, milk blood etc. And example of heterogeneous mixture is solution of sand and water ,concrete etc.

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Phosphine (PH3) can be prepared by the reaction of calcium phosphide , Ca3P2: based on this equation : Ca3P2 + 6H2O —-> 3 Ca(

MrMuchimi

Taking into account the reaction stoichiometry, you can observe that:

one mole of Ca₃P₂ produces 2 mol of PH₃.
the mole ratio between phosphine and calcium phosphide is 2 mol PH₃ over 1 mol Ca₃P₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

Ca₃P₂ + 6 H₂O → 3 Ca(OH)₂ + 2 PH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Ca₃P₂:1 mole
H₂O: 6 moles
Ca(OH)₂: 3 moles
PH₃: 2 moles

The molar mass of the compounds is:

Ca₃P₂: 182 g/mole
H₂O: 18 g/mole
Ca(OH)₂: 74 g/mole
PH₃: 34 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Ca₃P₂: 1 mole ×182 g/mole= 182 grams
H₂O: 6 moles× 18 g/mole= 108 grams
Ca(OH)₂: 3 moles ×74 g/mole= 222 grams
PH₃: 2 moles ×34 g/mole= 68 grams

<h3>Correct statements</h3>

Then, by reaction stoichiometry, you can observe that:

one mole of Ca₃P₂ produces 2 mol of PH₃.
the mole ratio between phosphine and calcium phosphide is 2 mol PH₃ over 1 mol Ca₃P₂.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

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1 year ago

Si desea preparar 300 gramos de una solución de azúcar en agua que tenga una concentración de 20% m/m en cuanto gramos de soluto

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Answer:

$m_{soluto}=60g$

Explanation:

¡Hola!

En este caso, al considerar la unidad de concentración de porcentaje masa/masa, podemos escribir su fórmula como:

$\%m/m=\frac{m_{soluto}}{m_{solucion}}*100\%$

Podemos identificar la masa de soluto (azúcar) como la incógnita, y resolverla como se muestra a continuación:

$m_{soluto}=\frac{\%m/m*m_{solucion}}{100\%}\\\\m_{soluto}=\frac{20\%*300g}{100\%}\\\\m_{soluto}=60g$

¡Saludos!

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3 years ago

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Answer:

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