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3 years ago

What is the difference between a homogeneous and a heterogeneous mixture?

Chemistry

1 answer:

Ne4ueva [31]3 years ago

7 0

Answer and explanation :

DIFFERENCE BETWEEN HOMOGENEOUS AND HETEROGENEOUS MIXTURE :

In homogeneous mixture the component which are present in the mixture all are in the same proportion whereas in heterogeneous mixture the component which are present in the mixture don't have the same proportion
We can not pick out the component of homogeneous mixture but in heterogeneous mixture we can pick out the components from the mixture
Example of homogeneous mixture is water, oil ,water sugar solution, milk blood etc. And example of heterogeneous mixture is solution of sand and water ,concrete etc.

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Give 3 example of a solid that sublimes.

tino4ka555 [31]

Here are a few examples :)

iodine (I2)

naphthalene

aresenic (As)

ferrocene

water (H2O)

carbon dioxide (CO2)

Hope this helps :)

5 0

3 years ago

How much energy does an X-ray with an 8 nm (8 x 10-9 m) wavelength have?

Vlada [557]

Answer: 2.48×10^-17 J

Explanation:

Given the following :

Wavelength = 8nm (8 x 10^-9 m)

Energy(e) of X-ray =?

Energy=[speed of light(c) × planck's constant (h)] ÷ wavelength

Speed of light = 3×10^8m/s

Planck's constant = 6.626×10^-34 Js

Wavelength = 8 x 10^-9 m

Energy = [(3×10^8) * (6.626×10^-34)] / 8 x 10^-9

Energy = [19.878×10^(8-34)] / 8 x 10^-9

Energy = 2.48475 × 10^(-26+9)

Energy = 2.48×10^-17 J

8 0

2 years ago

An 80.0-gram sample of water at 10.0°C absorbs 1680 Joules of heat energy. What is the final temperature of the water? a 50.0°C

ICE Princess25 [194]

Answer:

b)15.0°C

Explanation:

Specific Heat of Water=4.2 J/g°C

This means, that 1 g of Water will take 4.2 J of energy to increase its temperature by 1°C.

∴80 g Water will take 80×4.2 J of energy to increase its temperature by 1°C.

80×4.2 J=336 J

Total Energy Provided=1680 J

The temperature increase=\frac{\textrm{Total energy required}}{\textrm{energy required to increase temperature by one degree}}

Temperature increase= $\frac{1680}{336}$

=5°C

Initial Temperature =10°C

Final Temperature=Initial + Increase in Temperature

=10+5=15°C

7 0

3 years ago

If there is a graduated cylinder containing 20mL of water and a small rock is gently placed inside it, and the water level insid

LekaFEV [45]

Answer:

Explanation:

just subtract 20-25 and 5 is left over which is how much the water when up with the rock.

8 0

3 years ago

Read 2 more answers

To balance a chemical equation it may be necessary to adjust the

Mars2501 [29]

Answer:

To balance a chemical equation it may be necessary to adjust the coefficients.

Explanation:

The coefficients of a chemical equation are the numbers that you put in front of each reactant and product. They are used to balance the equation and comply with the law of mass conservation.

By adjusting the coefficients you obtain the relative amounts (moles) of each product and reactant, i.e. the mole ratios.

Here an example.

The first information is what is called a word equation. E.g. nitrogen and hydrogen react to form ammonia:

Word equation: hydrogen + nitrogen → ammonia

Skeleton equation: H₂ + N₂ → NH₃

This equation shows the chemical formulae but it is not balanced. The law of mass conservation is not observed.

So, in order to comply with the law of mass conservation you adjust the coefficients as follow.

Balanced chemical equation: 3H₂ + N₂ → 2NH₃

As you see, it was necessary to modify the coefficients. Now the law of conservation of mass is observed and you get the mole ratios:

3 mol H₂ : 1 mol N₂ : 2 mol NH₃

4 0

3 years ago