9g x 1/18.02= 0.499 rounded is 0.50
The question is incomplete, the complete question is;
A 31 g sample of a compound that contains only the elements C,H and N is completely burned in O2 to produce 44.0 g of CO2, 45.0 g of H2O, and 92.0 g of NO2. Determine the empirical formula of the compound.
Answer:
CH5N2
Explanation:.
Mass of C = 44.0g/44.0 g/mol = 1 mol * 1 = 1 mole of C
Mass of H = 45.0 g/18 g/mol = 2.5 moles * 2 = 5 moles of H
Mass of N = 92.0 g/46 g/mol = 2 moles * 1 = 2 moles of N
Dividing through by the lowest mole ratio;
1/1, 5/1, 2/1
1 : 5 : 2
Hence the empirical formula is;
CH5N2
Answer:
ammonium ion.
Explanation:
Check the box next to each molecule on the right that has the shape of the model molecule on the left: model molecules (check all that apply X 5 ? | O CH20 CNH, You can drag the slider to rotate the model molecule. + 1 O Brf 4 CH2Cl2 Note for advanced students: the length of bonds and size of atoms in the model is not necessarily realistic. The model is only meant to show you the general geometry and 3D shape of the molecule.
when you look at the diagram from the source page
one can conclude that the diagram is tetrahedral and the angle between the molecules is 109.5 deg
There is one central atom bonded to four atoms in a tetrahedral molecule .it has no lone electron pairs.m
NH4+ is the answer
Other molecules that are tetrahedral in shape are methane ion and phosphate ion.
Your answer should be A) Beryllium
Hope this helps:)