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jolli1 [7]
2 years ago
8

For the inverse variation function y = k/x (where x, k > 0), what happens to the value of y as the value of x increases? a. I

ncreases c. Increases then decreases b. Decreases d. Decreases then increases.
Mathematics
1 answer:
FrozenT [24]2 years ago
8 0

If the value of x increases then the value of y decreases. Then the correct option is B.

<h3>What is a function?</h3>

The function is an expression, rule, or law that defines the relationship between one variable to another variable. Functions are ubiquitous in mathematics and are essential for formulating physical relationships.

For the inverse variation function

\rm y = \dfrac{k}{x}    (where x, k > 0),

We know that the y is inversely proportional to the x.

Thus, if the value of x increases then the value of y decreases.

Therefore, the correct option is B.

More about the function link is given below.

brainly.com/question/5245372

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Step-by-step explanation:

Given integrals are:

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b) \int\limits^a_b {\sqrt{1+64cos^{2}(2x)} } \, dx---- (2)

Standard form

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<h3>Part A</h3>

compare (1) with standard form

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<h3>Part B</h3>

Compare (2) with standard form

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