A=πr²
pool=π(y-4)²=π(y²-8y+16)
total=π(y+4)²=π(y²+8y+16)
walkway=total-pool
walkway=π(y²+8y+16)-π(y²-8y+16)=
π(y²+8y+16-y²+8y-16)=
π(16y)=
16πy
first option is answer
y - y₁ = m(x - x₁)
y - 1 = 1³/₅(x - 2) Point - Slope Form
y - 1 = 1³/₅(x) - 1³/₅(2)
y - 1 = 1³/₅x - 3¹/₅
+ 1 + 1
y = 1³/₅x - 2¹/₅ Slope - Intercept Form
-1³/₅x - y = 1³/₅x - 1³/₅x - 2¹/₅
-1³/₅x - y = -2¹/₅
-1(-1³/₅x - y) = -1(-2¹/₅)
-1(-1³/₅x) + 1(y) = 2¹/₅
1³/₅x - y = 2¹/₅ Standard Form
1³/₅(0) - y = 2¹/₅
0 - y = 2¹/₅
-y = 2¹/₅
-1 -1
y = -2¹/₅ Y - Intercept
(x, y) = (0, -2¹/₅)
The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
<h3>What is the area of the rectangle?</h3>
It is defined as the area occupied by the rectangle in two-dimensional planner geometry.
The area of a rectangle can be calculated using the following formula:
Rectangle area = length x width
We have:
The length of a new rectangle playing field is 6 yards longer than quadruple the width.
Let's suppose the length is l and width is w of a rectangle:
From the problem:
l = 6 + 4w
Perimeter P = 2(l + w)
532 = 2(l + w)
Plug l = 6+4w in the above equation:
532 = 2(6 + 4w + w)
266 = 6 + 5w
260 = 5w
w = 52 yards
l = 6 +4(52) = 214 yards
Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
Learn more about the area of rectangle here:
brainly.com/question/15019502
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Is it multiple choice? If so, leave the answer choices.
Answer:
y = -4x +3
Step-by-step explanation:
the only thing you need from the equation is the slope, which is -4
y = -4x +3
