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4 years ago

A camel can drink 15 gallons of water in 10 minutes. at this rate, how much water can the camel drink in 99 minutes

Mathematics

2 answers:

Harman [31]4 years ago

8 0

99 minutes / 10 minutes = 9.9

15 gallons x 9.9 = 148.5 gallons total

Sergeu [11.5K]4 years ago

6 0

The answer will be 148.5 gallons of water.

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Imagine you are responsible for writing an advice column about mathematics. The following question is submitted to your column:

marissa [1.9K]

Explanation:

There are two different formulas that are useful with the given information:

Area = (1/2)ab·sin(C)

Area = √(s(s-a)(s-b)(s-c)) . . . where s=(a+b+c)/2

It does not matter which sides are designated a, b, and c. Angle C will be opposite side c.

The third angle can be computed based on the fact that the sum of angles in a triangle is 180°. It will be 180° -32° -28° = 120°. The least-to-greatest order of the angles is the same as the least-to-greatest order of the length of the opposite side. So, we might have ...

a = 7, A = 28°
b = 8, B = 32°
c = 13, C = 120°

Utilizing the first formula, the area is ...

Area = (1/2)(7)(8)sin(120°) = 14√3 ≈ 24.249 . . . square units

Utilizing the second formula, the area is ...

s = (7+8+13)/2 = 14

Area = √(14(14-7)(14-8)(14-13)) = 14√3 ≈ 24.249 . . . square units

For the answer to be complete, it should be noted that using either of the other two angles will give different results for the area. That is because those angles are not exact values, but are rounded to the nearest degree. Using the first formula with the different angles, we get ...

area = (1/2)(8)(13)sin(28°) ≈ 24.413 . . . square units
area = (1/2)(7)(13)sin(32°) ≈ 24.111 . . . square units

The first of these answers is a little high because 28° is a little more than the actual value of the angle. Likewise, the second of these answers is a little low because 32° is slightly smaller than the actual angle.

In short, the most accurate information available should be used if the answer is to be the most accurate possible. If the angles are exact, then their values should be used. If the side measures are exact, then their values should be used. In general, it will be easier to make accurate measurements of the side lengths than to make accurate angle measurements.

7 0

3 years ago

The graph below shows a line of best fit for data collected on the amount of time teenagers spend on the computer and

patriot [66]

Answer:

C) 30 minutes

Step-by-step explanation:

According to the line of best fit, when x=360, y=30, which means that a teenager spends 30 minutes watching television if they spend 360 minutes on the computer.

4 0

3 years ago

One-eighth of a number is -4,200. What is the number?

joja [24]

-33,600. To get this you multiply -4,200 by 8

4 0

3 years ago

Convert 6.28282828 in to a fraction

Irina-Kira [14]

Answer:

I got 6 and 28/99

Step-by-step explanation:

I put it in a calculator about 10 times and this was the answer every time, sorry if it wasn't helpful

5 0

3 years ago

Read 2 more answers

Prove A-(BnC) = (A-B)U(A-C), explain with an example

NikAS [45]

Answer:

Prove set equality by showing that for any element $x$ , $x \in (A \backslash (B \cap C))$ if and only if $x \in ((A \backslash B) \cup (A \backslash C))$ .

Example:

$A = \lbrace 0,\, 1,\, 2,\, 3 \rbrace$ .

$B = \lbrace0,\, 1 \rbrace$ .

$C = \lbrace0,\, 2 \rbrace$ .

$\begin{aligned} & A \backslash (B \cap C) \\ =\; & \lbrace 0,\, 1,\, 2,\, 3 \rbrace \backslash \lbrace 0 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace \end{aligned}$ .

$\begin{aligned}& (A \backslash B) \cup (A \backslash C) \\ =\; & \lbrace 2,\, 3\rbrace \cup \lbrace 1,\, 3 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace\end{aligned}$ .

Step-by-step explanation:

Proof for $[x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))]$ for any element $x$ :

Assume that $x \in (A \backslash (B \cap C))$ . Thus, $x \in A$ and $x \not \in (B \cap C)$ .

Since $x \not \in (B \cap C)$ , either $x \not \in B$ or $x \not \in C$ (or both.)

If $x \not \in B$ , then combined with $x \in A$ , $x \in (A \backslash B)$ .
Similarly, if $x \not \in C$ , then combined with $x \in A$ , $x \in (A \backslash C)$ .

Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ as required.

Proof for $[x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]$ :

Assume that $x \in ((A \backslash B) \cup (A \backslash C))$ . Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

If $x \in (A \backslash B)$ , then $x \in A$ and $x \not \in B$ . Notice that $(x \not \in B) \implies (x \not \in (B \cap C))$ since the contrapositive of that statement, $(x \in (B \cap C)) \implies (x \in B)$ , is true. Therefore, $x \not \in (B \cap C)$ and thus $x \in A \backslash (B \cap C)$ .
Otherwise, if $x \in A \backslash C$ , then $x \in A$ and $x \not \in C$ . Similarly, $x \not \in C \!$ implies $x \not \in (B \cap C)$ . Therefore, $x \in A \backslash (B \cap C)$ .

Either way, $x \in A \backslash (B \cap C)$ .

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ implies $x \in A \backslash (B \cap C)$ , as required.

8 0

3 years ago

A camel can drink 15 gallons of water in 10 minutes. at this​ rate, how much water can the camel drink in 99 ​minutes

A camel can drink 15 gallons of water in 10 minutes. at this rate, how much water can the camel drink in 99 minutes