-4 is less than -5 even though they are both on the same side of the number line. -4 is closer to zero.
Answer:
4 cm
Step-by-step explanation:
The ratio of AD to DC is 6:12 which is equivalent to 1:2. For the ratio of WZ to ZY, we want to find half of 8 cm from ZY, for this case, it is 4 cm which makes the ratio 4:8.
Okay, for this proof, I'll write the steps out.
Statements:
1. ABCD is a parallelogram
2. FG bisects DB
3. <GEB ≡ (pretend congruent symbol) <FED
4. DE ≡ BE
5. <CDA ≡ <ABC
6. < CDB ≡ <DBA
7. triangle DFE ≡ triangle BGE
8. FE ≡ GE
9. DB bisects FG
Reasons:
1. Given
2. Given
3. vertical angles are congruent
4. If bisected, then split into congruent parts
5. opposite angles of a parallelogram are congruent
6. Subtraction Property
7. ASA
8. CPCTC
9. segment split into congruent parts by other segment is bisected.
Hope this helped! :)
Answer: red is 13.36
Blue is 93.625
Step-by-step explanation:
Let the red marbles be y
Based on the question,red is 4times which means 4y
And blue is 7times greater than red which means 7(4y)
Blue + red=107
7(4y) + 4y=107
28y+4y=107
32y=107
Divide both sides by 32
Y=3.34
Red =4y
Red= 4(3.34)
Red =13.36
Blue= 7(4y)
Blue=7(4×3.34)
Blue= 93.625
C) 225m
Explanation:
Looking at the board we see each side is 25m in length. Each side has 5 squares, therefore the length of one side of each square is 5m (25m/5=5).
Let’s count how many full squares there are. There’s 5 completely full squares (one in the middle, and one on each of the four edges).
There’s also half-full squares which we COULD calculate separately using the area of a triangle. However, we know that two halves make one full square so let’s count how many full blocks these make up. There’s 8 triangles (or half full squares), therefore there are 4 full squares.
Adding this to the clearly full blocks shows 4+5=9. There are 9 fully shaded squares. The area of a square is A=s x s (Area = length of side x length of side). Therefore, one square’s area is 5x5=25m^2. The area of 9 squares is 25 x 9 = 225m^2.
Therefore the answer is C
