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kkurt [141]
3 years ago
15

Rewrite 10x - 5y = -30 in slope-intercept form. somebody help me wit dis

Mathematics
1 answer:
Anna [14]3 years ago
6 0

Answer:

y = 2x + 6

Step-by-step explanation:

10x - 5y = -30

-5y = -10x - 30

y = 2x + 6

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What is the surface area and volume of this figure?
Sophie [7]
Volume = 28 in squared
surface area = 44 in
6 0
3 years ago
What is the nth and the 10th term of this linear sequence<br> 6, 10,14, 18, 22
11111nata11111 [884]

Answer:

a_{10} = 42

Step-by-step explanation:

The n th term I obtained in your previous question, that is

a_{n} = 4n + 2

To find the 10 th term substitute n = 10 into the formula

a_{10} = 4(10) + 2 = 40 + 2 = 42

8 0
3 years ago
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The product of a positive number and 14 more than seven times the number is 105. Find the two numbers. first number =______ and
Nostrana [21]
Let the positive number be x

The expression is
x(14+7x)=105⇒ expanding the bracket gives,
14x+7 x^{2} =105 ⇒ rearranging to equate one side to zero
7x^{2} +14x-105=0 ⇒ Dividing each term by 7 to simplify
x^{2} +2x-15 ⇒ Factorising gives
(x+5)(x-3)=0
x=-5 and x=3

Hence, the first number is -5 and the second number is 3

8 0
4 years ago
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Find volume of cone z=sqrt(x^2+y^2) that is bounded with z=5 and z=7
Nina [5.8K]
Convert to cylindrical coordinates first, using

\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}

Then the volume is

\displaystyle\int_{\zeta=5}^{\zeta=7}\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=\zeta}r\,\mathrm dr\,\mathrm d\theta\,\mathrm d\zeta
=\displaystyle\pi\int_{\zeta=5}^{\zeta=7}\zeta^2\,\mathrm d\zeta
=\dfrac{218\pi}3
5 0
3 years ago
Given two concentric circles (circles that have the same center point), with the inner circle having a radius of 1 r and the out
Leno4ka [110]

Answer:

(x, y) ⇒ (2x, 2y)

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, rotation and dilation.

Dilation is the increase or decrease in size of a figure. If a figure with point A(x, y) is dilated by a scale factor of k, the new location is at A'(kx, ky). If k > 1, it is an enlargement and if k < 1, it is a reduction.

Given that the inner circle has a radius of 1 r and the outer one has a radius of 2 r. To map the inner circle onto the outer circle, the inner circle would need to be enlarged. The scale factor is:

k = outer circle radius / inner circle radius = 2r / 1r = 2

A dilation with a scale factor of 2 would be needed to map the inner circle onto the outer circle.

That is:

(x, y) ⇒ (kx, ky)

8 0
3 years ago
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