Answer:
See explanation
Step-by-step explanation:
Given 
According to the order of the vertices,
- side AB in triangle ABC (the first and the second vertices) is congruent to side AD in triangle ADC (the first and the second vertices);
- side BC in triangle ABC (the second and the third vertices) is congruent to side DC in triangle ADC (the second and the third vertices);
- side AC in triangle ABC (the first and the third vertices) is congruent to side AC in triangle ADC (the first and the third vertices);
- angle BAC in triangle ABC is congruent to angle DAC in triangle ADC (the first vertex in each triangle is in the middle when naming the angles);
- angle ABC in triangle ABC is congruent to angle ADC in triangle ADC (the second vertex in each triangle is in the middle when naming the angles);
- angle BCA in triangle ABC is congruent to angle DCA in triangle ADC (the third vertex in each triangle is in the middle when naming the angles);
The slope of this triangle is -2/1
Answer:
the Lateral SA is 84
The total is 1092.
Step-by-step explanation:
Answer:
We get x=3 and y=21
The ordered pair will be: (3,21)
Step-by-step explanation:
We need to use the substitution method to solve the system of equations.

For substitution method we substitute the value of x or y from one equation to other.
Let:

Putting value of y from equation 2 into equation 1

So, we get value of x=3
Now, for finding value of y, We substitute the value of x
Find value of x from equation 2

Now, putting value of x in equation 1

So, we get value of y=21
So, We get x=3 and y=21
The ordered pair will be: (3,21)
The completely factored equation is (a²b - 5)(4a²b - 1)
<h3>How to factor equation?</h3>
4a⁴b² - 21a²b + 5 = 0
let's expand the equation
Therefore,
4a⁴b² - 21a²b + 5 = 0
4a⁴b² - 20a²b - a²b + 5 = 0
Rearrange the equation
4a⁴b² - a²b - 20a²b + 5 = 0
Let's factorise the equation
4a⁴b² - a²b - 20a²b + 5 = 0
a²b(4a²b - 1) - 5(4a²b - 1) = 0
Therefore, the completely factored equation is as follows:
a²b(4a²b - 1) - 5(4a²b - 1) = 0
(a²b - 5)(4a²b - 1)
learn more on equation here: brainly.com/question/8842252
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