5 times the sum of a number and 27 is greater than or equal to 6 times the sum of that number and 26
1 answer:
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Answer:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
3*e-4-(6*e*(45+2*e))=0
Step by step solution :
STEP
1
:
Equation at the end of step 1
(3e - 4) - 6e • (2e + 45) = 0
STEP
2
:
STEP
3
:
Pulling out like terms
3.1 Pull out like factors :
-12e2 - 267e - 4 = -1 • (12e2 + 267e + 4)
Trying to factor by splitting the middle term
3.2 Factoring 12e2 + 267e + 4
The first term is, 12e2 its coefficient is 12 .
The middle term is, +267e its coefficient is 267 .
The last term, "the constant", is +4
Step-1 : Multiply the coefficient of the first term by the constant 12 • 4 = 48
Step-2 : Find two factors of 48 whose sum equals the coefficient of the middle term, which is 267 .
Step-by-step explanation:
