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Feliz [49]
3 years ago
9

Helphelphelphelphelphelphelphelphelphelphelphelphelphelphelphelpvv

Mathematics
2 answers:
ivann1987 [24]3 years ago
8 0

Answer:

I think the answer is B) 4.7

Step-by-step explanation:

just to let you know I maybe wrong.

Sophie [7]3 years ago
3 0

Answer:

4.4

Step-by-step explanation:

4.4

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Anthony writes a numerical expression 2+10x3-2 and says that the expression has a value of 34. Is Anthony correct? Explain your
lapo4ka [179]

Answer:

Anthony is incorrect

According to the order of operations(PEMDAS), you must first multiply 10 × 3

which equals 30, then you add 2, which equals 32, finally you subtract 2, which brings you back to 30

10 × 3 = 30

2 + 30 - 2 = 30

4 0
3 years ago
You gave your friend a short term 1.5 year loan of $30,000 at 2% compounded annually.
ElenaW [278]

Answer: $30,904.49

Step-by-step explanation:

I’m not sure if I did this right but it was the same was as the other question

4 0
3 years ago
Explain which situation will give you the best price: a discount of 15% and then 10% off that amount, a discount of 10% and then
Anuta_ua [19.1K]

Answer: a discount of 25%

Step-by-step explanation:

if you take any number and take 10 percent off then 15 percent off it’s even but 25 percent off is a better discount because it takes more money off the original price

4 0
3 years ago
Read 2 more answers
Analyzing Graphs to Determine Input Values
miv72 [106K]

Answer:

Step-by-step explanation:

se the graph to determine the input values that

correspond with f(x) = 1.

O x=4

O x= 1 and x = 4

O x= -7 and x = 4

O x= -7 and x = 2

6.

(-6, 4)

4

(1,4) w

2

(-7, 1)

(2, 1) x

2

4

-8/ -6 -4 -2

-2

-4

7 0
3 years ago
The lateral edge PA of a triangular pyramid ABCP is perpendicular to the base and PA = 2sqrt5 in. The base edges AB = 10 in, AC
DIA [1.3K]

Answer:

PQ = √84 = 2√21 in ≈ 9.165 in

Step-by-step explanation:

The base edges AB = 10 in, AC = 17 in, and BC = 21 in

Q ∈ BC and AQ is the altitude of the base.

Let BQ = x in ⇒ CQ = (21 - x) in

ΔAQB a right triangle at Q

∴ AQ² = AB² - BQ² = 10² - x²  ⇒(1)

ΔAQC a right triangle at Q

∴ AQ² = AC² - CQ² = 17² - (21-x)²  ⇒(2)

Equating (1) and (2)

∴  10² - x² = 17² - (21-x)²

∴ 10² - x² = 17² - (21² - 42x + x²)

∴  10² - x² = 17² - 21² + 42x - x²

∴ 10² - 17² + 21² = 42x

∴ 42x = 252

∴ x = 252/42 = 6

Substitute at (1)

∴ AQ² = AB² - BQ² = 10² - x² = 100 - 36 = 64 = 8²

∴ AQ = 8 in

∵ The lateral edge PA of a triangular pyramid ABCP is perpendicular to the base

∴ PA⊥AQ

∴ ΔPAQ is a right triangle at A,

PA = 2sqrt5 in  and AQ = 8 in

∴ PQ (hypotenuse) = √(PA² + AQ²)

∴ PQ = √[(2√5)² + 8²] = √(20+64) = √84 = 2√21 in ≈ 9.165 in

6 0
3 years ago
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