Triangles JFE and JLK are similar provided that line segments FE and LK are parallel. This means that corresponding parts of these triangles occur proportionally to one another. In particular,

$\dfrac{JF}{JL}=\dfrac{JE}{JK}=\dfrac{FE}{LK}$

From this relation we get

$\dfrac{JF}{JL}=\dfrac{JE}{JK}\implies\dfrac{(3x+21)-12}{12}=\dfrac{56}{70}$

Now we can solve for $x$ :

$\dfrac{3x+9}{12}=\dfrac45$

$3x+9=12\cdot\dfrac45=\dfrac{48}5$

$3x=\dfrac{48}5-9=\dfrac35$

$x=\dfrac{\frac35}3=\dfrac15$

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Which of the following expressions is equal to -3x2 +27?

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Answer:

its B or C

Step-by-step explanation:

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What is 2,800 divided by 64

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Answer:

43.75

Step-by-step explanation:

jejejdjdjdudururjrjdjrir

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Combine like-terms of 6x-2x-2=-3x+4(x+7)

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