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Roman55 [17]
3 years ago
13

Joshua has a bag of marbles. In the bag are 5 white marbles, 3 blue marbles, and 7 green marbles. Peter randomly draws one marbl

e, sets it aside, and then randomly draws another marble. What is the approximate probability of Peter drawing out two green marbles
Mathematics
1 answer:
Step2247 [10]3 years ago
6 0

Answer:

1 / 5

Step-by-step explanation:

Given that:

Number of white marbles = 5

Number of blue marbles = 3

Number of green marbles = 7

Required is the approximate probability of drawing 2 green marbles, Note that drawing is done without replacement :

Probability = required outcome / Total possible outcomes

Total possible outcomes = sum of all marbles = (5 + 3 + 7) = 15 marbles

First draw:

P(Green) = 7 / 15

Second draw:

Required outcome = 7 - 1 = 6

Possible outcomes = 15 - 1 = 14

P(green) = 6 / 14

Probability of drawing out two green marbles :

(7/15 * 6/14) = 42 / 210 = 1 / 5

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Paha777 [63]

Answer:

A. 35

Step-by-step explanation:

a || b .....(given)

line c is their transversal.

-> x° + (3x + 40)° = 180° (Interior angles on the same side of transversal)

-> (3x + 40 + x)° = 180°

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7 0
2 years ago
Which of these is the algebraic expression for "5 times the sum of 2 and y?" (1 point)
Mumz [18]

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B. 2 + 5 ⋅ y

C. 2(5 + y)

D. 5(2 + y) ✔

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8 0
3 years ago
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Vikentia [17]

Answer:

D

Step-by-step explanation:

6 0
3 years ago
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Abbie has to do 25 math problems tonight. She has completed 40%. How many problems has she completed?
erik [133]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
4 - 2(x-4)/ 3= 3(2x+5)/2<br>pls answer fast​
omeli [17]

Answer:

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