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Solnce55 [7]
3 years ago
14

Convert 15/9 to a decimal. A. 1.64 B. 1.67 C. 1.66 D, 1.69

Mathematics
1 answer:
Travka [436]3 years ago
7 0
15/9 = 1.6666... (where 6 repeats infinitely)

If we're rounding to 2 decimal places, 6 will round up to 7

Therefore, B. 1.67 is your answer
You might be interested in
A certain chain of ice cream stores sells 28 different flavors, and a customer can order a single-, double- , or triple-scoop co
astra-53 [7]
<span>Think about the cones with only 1 scoop of ice cream. Isn't it clear that there are 28 of those?
Now think about the two scoop cones. You have 28 choices for the first scoop and 28 choices for the second scoop.
So the number of possibilities is 28(28).
Now think of the 3 scoop cones.
You have 28 choices for the first scoop, 28 choices for the second scoop, and 28 choices for the third scoop or 28(28)(28) possibilities.
Add them all together and you have the total.

So it will be like this:
</span><span>28^3+28^2+28
</span>
I hope my answer helped you.
6 0
3 years ago
HELP PLEASEEE EMERGENCY
dezoksy [38]

Answer:

y=2/3×+6

Step-by-step explanation:

y-2=2/3(×+6)

y=2/3x4+2

y=2/3×+6

5 0
3 years ago
Gabby has a goal to finish covering the field before 12 hours have
wolverine [178]
Gabby has a goal to finish covering the field before 12 hours have
elapsed.
Explain why Gabby will be able to meet her goal by working at this rate. As
part of the explanation, determine the amount of time, in hours, Gabby
will have to water the field.
5 0
2 years ago
Evaluate the determinant of the matrix.<br> -4 5 6<br> 0 4 4<br> -2 -5 4<br> I need the work plz
FromTheMoon [43]

Answer:

-136

Step-by-step explanation:

We have to find the determinant of the following matrix:

\left[\begin{array}{ccc}-4&5&6\\0&4&4\\-2&-5&4\end{array}\right]

We can find the determinant by expanding via 1st column. i.e. by taking each element of 1st column and multiplying it by its co-factor matrix as shown below:

det \left[\begin{array}{ccc}-4&5&6\\0&4&4\\-2&-5&4\end{array}\right]

= (-4 \times det \left[\begin{array}{cc}4&4\\-5&4\end{array}\right]) - (0 \times (-4 \times det \left[\begin{array}{cc}5&6\\-5&4\end{array}\right]))+ ((-2) \times det\left[\begin{array}{cc}5&6\\4&4\end{array}\right])\\\\ =-4 \times (16 + 20)-(0)+(-2 \times 20-24)\\\\ =-4(36)+(-2(-4))\\\\ =-144+8\\\\ =-136

The notation det() stands for determinant of the matrix.

Therefore, the determinant of the given matrix is -136

8 0
3 years ago
When multiplying bases with exponent, you always multiply the exponents True or false
patriot [66]

Answer: no, you add the exponents.

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
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