The rectangle has a perimeter P of 58 inches.The length l is one more than 3 times the width w.write and solve a system of linear equations to find the length and width of the rectangle?
Answer:
Length(L)=22 inches
Width(W) = 7 inches
Step-by-step explanation:
GIven:-
Perimeter (p)=58 inches,
Length(L)= one more than 3 times the width(W)
Let, W=x ---------------------------------(equation 1
-----------------------(equation 2)
Here x is unknown and to find the Width(W) we have to find the value of x.
Now,
Perimeter of rectangle(p) = 2 times length(L) + 2 times width(W)
----------------(from equation 1)
----------------(given p=58 inches)
----------------------(equation 3)
Now substituting the value of equation 3 in equation 2.
as, 
-----------------------(from equation 1)
inches -------------------(equation 3)
Therefore, Length(L) = 22 inches and Width(W) = 7 inches.
Answer:
1000%
Step-by-step explanation:
Alright
for a 45-45-90 triangle, if the legs are x then the hytponuse is x√2
so LM=x√2 is right
NM=x
also, tan=oposite side/adjacent side
so that would be LN/MN or MN/LN=x/x=1
so that would be tan(45)=1
so you want to check the 1st one, 3rd one and 5th one
NM=x
LM=x√2
tan(45°)=1 are the answers
Answer:
38.5
Step-by-step explanation:
First do 77/2 then you get 38.5, if anything is wrong please tell me!!
Greatest to least is 3 1/2 , 3 , 1/3 , 0.3 , 0.03
Hope im right
