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Anton [14]
3 years ago
5

An athlete trains on a circular track of radius 40 m and jogs 10 laps each day, 5 days a week. How far does he jog each week? Ro

und the answer to the nearest whole number of metres.
Mathematics
1 answer:
mariarad [96]3 years ago
5 0
Length of a circle=2πr
r=40 m
Length of the circular track=2*π*40m=80π m.

The athelete jogs each day 10 laps
1 lap-------------------80π m
10 laps-------------   x
x=(10 laps * 80π m) / 1 lap=800π m

Calculate how far he jog eache week (5 days).
1 day------------------800π m
5 days----------------   x
x=(5 days*800π m)/1day=4000π m=4000m * 3.141592...≈12566,37 m

solution: 12566 m

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8:16 and 7:14

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5:10 is a 1 to 2 ratio and so are 8:16 and 7:14

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The midpoint of mn is point p at (-4,6). If point m is at (8,-2), what are the coordinates of point n?
VashaNatasha [74]
<u>x₁ + x₂</u>                             <u>y</u>₁ + <u>y</u>₂<u>
</u>     2      = M                        2     = M
<u>
x + 8</u>                                 <u>y + -2</u><u>
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<u>multiply both sides by 2.

</u>x+8=-8                             y - 2 = 12
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0.84

Step-by-step explanation:

Given that Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are summarized as follows:

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We are to find out P(A'UB)

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P(AUB) =P(A)+P(B)-P(A\bigcap B)\\0.95=0.86+0.79-P(A\bigcap B)\\P(A\bigcap B)=0.70

P(A'UB) = P(A')+P(B)-P(A' \bigcap B)\\= 1-P(A) +P(B)-[P(B)-P(A \bigcap B)]\\= 1-0.86+0.79-P(B)+[tex]P(A'UB)=0.14+0.79-0.79+0.70\\=0.84P(A \bigcap B)[/tex]

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