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The probability that a red ace is drawn first and then a black ace is mathematically given as
x=1/4
<h3>What is the probability that a red ace is drawn first and then a black ace?</h3>Where
Sample mean=(x,y)\, x, y \in \{h,d,c,s\}
If we want a player to draw two cards of the same color from their deck, the following combinations of cards are appropriate choices:
Generally, 8 possible pairings above 16. This indicates that the likelihood of a player drawing two cards of the same color is 8/16, which is equivalent to a probability of half.
In conclusion, In a similar vein, the following pairs of cards illustrate the likelihood of obtaining a black ace after having drawn a red ace in the previous round:
Giving
x=4/16
x=1/4
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Answer: A & B are the same answer --> 96, max
<u>Step-by-step explanation:</u>
Consider m is the degree of the numerator (top) and n is the degree of the denominator (bottom). Then the horizontal asymptote (H.A.) is based on the relationship between m and n:
- If m > n, then there is no H.A.
- If m = n, then y = coefficient of numerator ÷ coefficient of denominator
- If m < n, then y = 0
In the given problem, m = 1 and n = 1 so the H.A. is:
This is the maximum number of moose that the forest can sustain at one time.