Answer:
The equation for rational function for given asymptotes is
f(x)=(-4x^2-6)/{(x-3)(x+3)}
Step-by-step explanation:
Given:
vertical Asymptotes at x=3 and x=-3 and a horizontal asymptote at
y=-4 i.e parallel to x axis.
To find:
equation of a rational function i.e function in form p/q
Solution;
the equation should be in form of p/q
Numerator :denominator.
Consider f(x)=g(x)/h(x)
as vertical asymptote are x=-3 and x=3
denominator becomes, (x-3) and (x+3)
for horizontal asymptote to exist there should have same degrees in numerator and denominator which of '2'
when g(x) will be degree '2' with -4 as coefficient and dont have any real.
zero.
By horizontal asymptote will be (-4x^2 -6)
The rational function is given by
f(x)=g(x)/h(x)
={(-4x^2-6)/(x-3)(x+3)}.
Answer: m∠1 = 32°
Step-by-step explanation:
Since we have given that
The angled support making angle with the floor = 32°
So, we need to find the measure of angle 1 so that the steps are parallel to the floor.
As we know that "To make parallel to the floor , there should be alternate interior angle which must be equal."
So, m∠1 = 32° ( the angled support making angle with the floor)
Hence, m∠1 = 32°
Answer:
19
Step-by-step explanation:
7(<u>2 + 3</u>) − 4 · 2² ← like that right so
<u>parenthesis first add the numbers up↓</u>
7(5) - <u>4</u> · 2²
write number in exponential form↓
<u>7(5)</u> - 2²· 2²
multiply↓
35 - <u>2² · 2²</u>
calculate the product↓
35 - <u>2⁴</u>
evaluate the power↓
35-16
then subtract↓
19
Answer:
x < 1/2 and x>2
Step-by-step explanation:
first solve the eqn,
2x2 -5x +2 = 2x2 -4x -x +2 = 2x(x-2) - 1(x-2) = (2x-1)(x-2)
since the questions asks for >,
x < 1/2 and x>2
if the question had asked for <,
1/2<x<2
