Answer:
75/256 in³ < 64/125 in³
Step-by-step explanation:
First, find the volumes of the two 3-D figures:
For Figure 1:
Using the volume formula:
V = l × w × h
= 6/8 × 5/8 × 5/8
= (6/8 × 5/8) × 5/8
= 30/64 × 5/8
V = 150/512
Simplify:
V = 75/256
So Figure 1's volume is 75/256 in³.
For Figure 2:
V = l × w × h
= 4/5 × 4/5 × 4/5
= (4/5 × 4/5) × 4/5
= 16/25 × 4/5
= 64/125
So Figure 2's volume is 64/125 in³.
Now, comparing the two volumes:
You can cross multiply the fractions to figure out which fraction is greater:
Figure 1 Figure 2
<u> 75 </u> = <u> 64 </u>
256 125
75 (125) = 256 (64)
9375 = 16384
So Figure 2 has the greater volume.
Your final result should be:
75/256 in³ < 64/125 in³
Answer:
When the range is wide
Step-by-step explanation:
Answer:
10 cm by 5cm
Step-by-step explanation:
We know that for every 5 meters, there will be 1 centimeter. The pool is 50 meters by 25 meters. So to find this in terms of centimters, divide by 5 to get 10 cm by 5 cm.
Answer:
Step-by-step explanation:
Given that population average is 0.8 ampere
Sample size = 9
Sample mean x bar = 1.34 A
Sample std dev s = 0.48
(one tailed test)
Mean difference - 
Std error = 
t test can be used since sigma is not known and sample size small
t statistic = mean diff/std error = 3.5
df = 8
p value = 0.00404
