Answer:
D. x=5
The answer is x=4.50 then it is rounded off to 5. So, the answer is 5.
Step-by-step explanation:
Find the domain of the inequality:
Rearrange terms to the left side of the equation:
Divide both sides of the inequality by the coefficient of the variable:
=> 
The domain of the inequality is:
Convert logarithm to exponential form:
Calculate the power:
Rearrange terms to the left side of the equation:
Calculate:
Divide both sides of the equation by the coefficient of the variable:
=> 
=>
Round the number: 
Answer: 
=> 
Read to know more about log equation:
brainly.com/question/16692243?referrer=searchResults
#SPJ10
Answer:
16(4b - c)
Explanation:
16 x 4b = 64b
16 x c = 16c
Answer:
C. 
Step-by-step explanation:
I think the equation meant
?
Anyways, to factor these kinds of quadratic, keep into consideration:

ONLY if:

Start off by finding factors of c, which in this case, -18:
±(1, 2, 3, 6, 9, 18)
If one of the numbers is negative then the other number must be positive.
Find which two factors will sum up to b, which in this case, is 3.

The only two factors that work are 6 and -3.
Replace them into the factored form:

Answer:
Standard Error of the difference = 0.0695
Step-by-step explanation:
Its given that : In a large school district, 16 of 85 randomly selected high school seniors play a varsity sport

Also, in the same district, 19 of 67 randomly selected high school juniors play a varsity sport

Now, finding the standard error of the difference :

Hence, Standard Error of the difference = 0.0695