Answer:
Probability of both even is 12×12=14. Given they are both even there are 3 possible even numbers: 2,4,6.
Step-by-step explanation:
The distance are
a. 42.42
b. 15. 52
<h3>How to solve for the distance</h3>
80 = 65 + <ABC
<ABC = 80 - 65
= 15
Through the use of sine rule we would have
By using sine rule,
Sine 15/a = sine 135/b =
sin 30/30.
Next we have to solve b by cross multiplying
b = (30× sin135) / sin 30
= 21.21/0.5
b = 42.42 km
Also, the value of a will be:
= (42.42 × sin 15) / sin 135
= 10.98/0.7071
= 15.52
Read more on bearing here:
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Answer:
Yes
Step-by-step explanation:greatest common factor (GCF) of 10 and 14 is 2. We will now calculate the prime factors of 10 and 14, then find the greatest common factor (greatest common divisor (gcd)) of the numbers by matching the biggest common factor of 10 and 14.
Divide the figure using vertical lines into 3 sub-areas. You have already done this on the left side of the figure. The base of this trapezoid is (30-10 -12) ft, or 8 ft. The trapezoid has 2 heights shown: one is 11 ft and the other is 15 ft.
The area of this trap. is [ (11 ft + 15 ft)/2 ] * [8 ft] ], or 13*8 ft^2, or 104 ft^2.
Next is the rectangle in the middle. Its height is 15 ft and its width is 12 ft. Its area is (15 ft)(12 ft) = 180 ft^2.
Last is the trapezoid on the right. Its base is 10 ft and the average of its heights is [(15+7.5) ft] / 2, or 11.25 ft. Thus, the area of this trap. is
(11.25 ft)(10 ft) = 112.5 ft^2.
Add these 3 sub-areas together to get the total area.
Good luck!!
