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Kryger [21]
3 years ago
15

a cell phone company charges $40 per month for unlimited calling, and $0.20 per text message sent. if f represents the number of

text messages roxy sent last month, which expression represnts the cost of her bills last month before any taxes or additional fees?
Mathematics
2 answers:
Svetlanka [38]3 years ago
6 0
Okay Adiara- 

You have to pay $40 for the calling. So even if you don't text anyone (yeah right), you'd have to pay the $40. 

Now for those texts- $.10 each. But how many are you going to text? 5? 500? 50,000? We don't know just yet so we have to use a variable...let's call it t for texts. Each text costs $.10. In math, "each" means multiply. $.10 multiplied by the number of texts you send. 



Now we need to put those together- the $40 for calling and the $.10 * t for the texts. Put together...combine...ADD!

40 + .10t

Make sense?
ankoles [38]3 years ago
3 0
The expression would be $0.20 x f. Once you figure out what the 'f' variable stands for, you have to multiply it by $0.20, and you will have your answer.
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<h2>y = -5x -18</h2>

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4 years ago
-3|9x-7|=2 Find the answer for x
labwork [276]
<h2>Solving Equations with Absolute Expressions</h2><h3>Answer:</h3>

<u>No Solutions</u>

<h3>Step-by-step explanation:</h3>

Given:

-3|9x -7| = 2

Rewriting the given equation:

-3|9x -7| = 2 \\ |9x -7| = -\frac{2}{3}

We have to realize that the right side of the equation, |9x -7|, will always be positive no matter what real values of x (because we're taking the absolute value of the expression) and we are equating it to a <em>negative</em> constant number, -\frac{2}{3}\\. Something that is always positive will never be negative so there's no value for x that satisfies the solution.

\rule{6.5cm}{0.5pt}

<em>You</em><em> </em><em>may</em><em> </em><em>not</em><em> </em><em>read</em><em> </em><em>the</em><em> </em><em>following</em><em> passage</em><em> </em><em>that</em><em> </em><em>I</em><em> </em><em>have</em><em> </em><em>written.</em>

\rule{6.5cm}{0.5pt}

Solving by positive of the expression:

9x -7 = -\frac{2}{3} \\ 9x = -\frac{2}{3} +7 \\ 9x = -\frac{2}{3} +\frac{21}{3} \\ 9x = \frac{19}{3} \\ 9x \times \frac{1}{9} = \frac{19}{3} \times \frac{1}{9} \\ x = \frac{19}{27}

Solving by the negative of the expression:

-(9x -7)= -\frac{2}{3} \\ 9x -7 = \frac{2}{3} \\  9x = \frac{2}{3} +7 \\ 9x = \frac{2}{3} +\frac{21}{3} \\ 9x = \frac{23}{3} \\ 9x \times \frac{1}{9} = \frac{23}{3} \times \frac{1}{9} \\ x = \frac{23}{27}

Checking: x = \frac{19}{27}\\

-3|9(\frac{19}{27}) -7| \stackrel{?}{=} 2 \\ -3|\frac{19}{3} -7| \stackrel{?}{=} 2 \\ -3|\frac{19}{3} -\frac{21}{3}| \stackrel{?}{=} 2 \\ -3|-\frac{2}{3}| \stackrel{?}{=} \\ -3(\frac{2}{3}) \stackrel{?}{=} 2 \\ -2 \stackrel{?}{=} 2 \\ -2 \neq 2

x = \frac{19}{27}\\ is an extraneous solution.

Checking: x = \frac{23}{27}\\

-3|9(\frac{23}{27}) -7| \stackrel{?}{=} 2 \\ -3|\frac{23}{3} -7| \stackrel{?}{=} 2 \\ -3|\frac{23}{3} -\frac{21}{3}| \stackrel{?}{=} 2 \\ -3|\frac{2}{3}| \stackrel{?}{=} \\ -3(\frac{2}{3}) \stackrel{?}{=} 2 \\ -2 \stackrel{?}{=} 2 \\ -2 \neq 2

x = \frac{23}{27}\\ is an extraneous solution.

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