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3 years ago

Slope-intercept passes through (-2,1) and (2,-5)

Mathematics

1 answer:

Elenna [48]3 years ago

3 0

I wish i knew but i need points sorry

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HELPP!!!!!

Alja [10]

Answer:

choice b

Step-by-step explanation:

3.49

____ = 0.1396 ≈ 0.14 or 14 cents per ounce

4.79

____ = 0.10644444 ≈ 0.11 or 11 cents per ounce

3 0

2 years ago

Please answer ASAP! <br> All help is deeply appreciated!

Darina [25.2K]

Answer:

I am going to have to go with B. (How many text messages do you send each day?) This will get you the data needed because it is specific. D would also work but I went with C because D is less informative and less specific about how often people use their phones. Hope that this helped! Please tell me if you have any more questions! Have a great day!

4 0

3 years ago

A high school class consists of 5 seniors, 10 juniors, 13 sophomores, and 4 freshmen. Exactly 4 of the juniors are male, and

lozanna [386]

Answer:

The probability that the pair consists of a female junior and a male sophomore is 0.096

Step-by-step explanation:

No of male juniors=4

No of female juniors=10-4=6

No of female sophomores=5

No of male sophomores=13-5=8

As per question,

Probability that the pair consists of a female junior and

a male sophomore = $\frac{6C1\times8C1}{32C2}$ =0.096

Therefore, the probability that the pair consists of a female junior and a male sophomore is 0.096

7 0

3 years ago

Determine whether each integral is convergent or divergent. If it is convergent evaluate it. (a) integral from 1^(infinity) e^(-

AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

$\int_1^{\infty} e^{-2x} dx=\left[-\frac{e^{-2x}}{2}\right]_1^{\infty}\\\\\int_1^{\infty} e^{-2x} dx=-\frac{e^{-\infty}}{2}+\frac{e^{-2}}{2}\\\\\int_1^{\infty} e^{-2x} dx=\frac{e^{-2}}{2}\\$

So, this integral is convergent.

$\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\$

So, this integral is divergent.

$\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\$

So, this integral is divergent.

4 0

3 years ago

Find the values of x and y.

gulaghasi [49]

Answer:

y=180-63-63/2=27degree...in triangle mln

x=180-27-63=90....in triangle mon

6 0

2 years ago

Read 2 more answers