3 years ago

I need a little bit of help here ☹️

1 answer:

3 0

-3(y+2)^2 - 5 + 6y
= -3(y^2 + 4y + 4) - 5 + 6y
= -3y^2 - 12y - 12 - 5 + 6y
= -y^2 - 6y - 17

Answer
(-1) y^2 + (-6) y + (-17)

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Identify the vertex for the graph of y = 2x2 + 8x − 3. (2, 21) (2, 17) (−2, −11) (−2, −27)

Finger [1]

$\bf \textit{vertex of a vertical parabola, using coefficients}
\\\\
\begin{array}{lcccl}
y = & 2x^2& +8x& -3\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\qquad 
\left(-\cfrac{ b}{2 a}\quad ,\quad c-\cfrac{ b^2}{4 a}\right)
\\\\\\
\left( -\cfrac{8}{2(2)}~~,~~-3-\cfrac{8^2}{4(2)} \right)\implies \left( \cfrac{-8}{4}~~,~~-3-\cfrac{64}{8} \right)
\\\\\\
\left(-2~~,~~-3-8 \right)\implies (-2~~,~~-11)$