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Hunter-Best [27]
3 years ago
7

Will anyone please answer my questions? qwq they're kind of important since they're for an assignment that's due today...

Mathematics
1 answer:
Anarel [89]3 years ago
5 0

Answer:

I answered a few.

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Nate rented a power washer and a generator. On his first job, he used each piece of equipment for 6 hours which cost $90. On his
sp2606 [1]

Answer:

Step-by-step explanation:

p = power washer and g = generator

6p + 6g = 90 .....multiply by 4

4p + 8g = 100 ....multiply by -6

---------------------

24p + 24g = 360 (result of multiplying by 4)

-24p - 48g = -600 (result of multiplying by -6)

---------------------add

-24g = - 240

g = -240 / -24

g = 10 <=== the generator cost $ 10 per hr

6p + 6g = 90

6p + 6(10) = 90

6p + 60 = 90

6p = 90 - 60

6p = 30

p = 30/6

p = 5 <==== the power washer costs $ 5 per hr

check...

4p + 8g = 100

4(5) + 8(10) = 100

20 + 80 = 100

100 = 100 (correct)

3 0
3 years ago
Solve for x 11x-7= 3x+9
elixir [45]

Answer: x=2

Step-by-step explanation:

first subtract 3x from both sides

then your equation will be 8x-7=9 then you will add 7 to both sides getting 8x=16 then divide both sides by 8 and x=2

5 0
3 years ago
A radio station is giving away tickets to a play. They plan to give away tickets for
galben [10]

Answer:

IDK

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
tess has 100 dimes and quarters , if the total of the coins is $21.40 how many of each of the coins does she have ?? Using subst
Zanzabum

Answer: 24 and 76

Step-by-step explanation:

{

d

+

q

=

100

10

d

+

25

q

=

2140

From the first equation, we have  

d

=

100

−

q

Substituting that into the second equation, we have

10

(

100

−

q

)

+

25

q

=

2140

⇒

1000

−

10

q

+

25

q

=

2140

⇒

15

q

=

1140

⇒

q

=

1140

15

=

76

Knowing that  

q

=

76

we can substitute that value into the first equation to obtain

d

+

76

=

100

∴

d

=

24

Thus, Sue has  

24

dimes and  

76

quarters.

4 0
3 years ago
Martha has widow's peak and attached earlobes. Martha's dad had a straight hairline and unattached earlobes. If Martha marries a
krok68 [10]

Answer:

the probability of having a widow peak and attached earlobe = 0.6667*0.66667 = 0.4445 = 44.5%

Step-by-step explanation:

Martha = widow's peak + attached earlobes.

Martha's dad = straight hairline + unattached earlobes.

Martha husband =straight hairline+ widow's peak + attached earlobes

what is the probability that Martha child will have a widow's peak + attached earlobes?

since,

Martha + Martha husband =straight hairline+ widow's peak + attached earlobes

the probability of the child having widow peak is 2/3 = 0.6667

the probability of the child having attached earlobes is 2/3 = 0.66667

the probability of having both = 0.6667*0.66667 = 0.4445

6 0
3 years ago
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