Original points are:
x = (3, -1); y = (4,-4); z = (1,-2).
A reflection across the line y = 1 (a line parallel to the y-axis) will keep the same x-coordinates and will move the y-coordinate upward as many units above the line y = 1 as units are from the line y = 1 to the y-coordinate of the original point.
Distance of (3,-1) to the line y = 1 is 1 - (-1) = 2 => new y-coordinate = 1 + 2 = 3.
<span>So, the answer is that the ordered pair ox x' is (3,3)</span>
5 or 1/2 since it's numerator and denominator are integers
Answer:
B. 0.43, -0.43
Step-by-step explanation:
The given equation is
![-2=3-7\sqrt[5]{x^2}](https://tex.z-dn.net/?f=-2%3D3-7%5Csqrt%5B5%5D%7Bx%5E2%7D)
Combine similar terms to get:
![-2-3=-7\sqrt[5]{x^2}](https://tex.z-dn.net/?f=-2-3%3D-7%5Csqrt%5B5%5D%7Bx%5E2%7D)
![-5=-7\sqrt[5]{x^2}](https://tex.z-dn.net/?f=-5%3D-7%5Csqrt%5B5%5D%7Bx%5E2%7D)
![\sqrt[5]{x^2}=\frac{5}{7}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E2%7D%3D%5Cfrac%7B5%7D%7B7%7D)
![x^2=(\frac{5}{7})^5](https://tex.z-dn.net/?f=x%5E2%3D%28%5Cfrac%7B5%7D%7B7%7D%29%5E5)
![x^2=\frac{3125}{16807}](https://tex.z-dn.net/?f=x%5E2%3D%5Cfrac%7B3125%7D%7B16807%7D)
![x=\pm \sqrt{\frac{3125}{16807}}](https://tex.z-dn.net/?f=x%3D%5Cpm%20%5Csqrt%7B%5Cfrac%7B3125%7D%7B16807%7D%7D)
![x=\pm 0.43](https://tex.z-dn.net/?f=x%3D%5Cpm%200.43)
or ![x=-0.43](https://tex.z-dn.net/?f=x%3D-0.43)
The correct answer is B.
For these fractions, you need to find a number that can divide the numerator and denominator by the same number. It needs to be simplified down till it can't be simplified any more.
1. 1/9
2. 12/18
3. 5/6
4. 36/45
5. 5/8
6. 6/8
7. 10/12
8. 20/36