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ratelena [41]
3 years ago
10

Kathy is a repair technician for a phone company. Each week, she receives a batch of phones that need repairs. The number of pho

nes that she has left to fix at the end of each day can be estimated with the equation P=108−23d P = 108 − 23 d , where P is the number of phones left and d is the number of days she has worked that week. What is the meaning of the value 108 in this equation?
Mathematics
1 answer:
Semenov [28]3 years ago
7 0

Answer:

What 108 represents here is that the total number of phones she has to fix each week is 108 phones

Step-by-step explanation:

The linear equation is

P = 108-23d

compare this with the general form;

y = mx + c

we have;

P = -23d + 108

We can see that 108 represents the y-intercept in this case

The x-value at the y-intercept is 0

So what this mean is that the number of phones she has to fix each week is 108

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$900

Step-by-step explanation:

If she holds $500 and she is charged 15%; it means

The interest she pays per month is ;

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Then annually meaning for 12 months, she pays;

$75 × 12 = $900

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What 76 rounded to the nearest 10
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76 rounded to the nearest 10 is 80.

Since 6 is greater than 5, it rounds 7 to 8.
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g A sample of 3 items is chosen at random from a box containing 20 items, out of which 4 are defective. Let X be the number of d
professor190 [17]

Answer:

The variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

The variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

Step-by-step explanation:

The variable <em>X</em> is defined as, <em>X</em> = number of defective items in the sample.

In a sample of 20 items there are 4 defective items.

The probability of selecting a defective item is:

P (X)=\frac{4}{20}=0.20

A random sample of <em>n</em> = 3 items are selected at random.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 3 and <em>p </em>= 0.20.

The variance of a Binomial distribution is:

V(X)=np(1-p)

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)=3\times0.20\times(1-0.20)=0.48

Compute the standard deviation (σ (X)) as follows:

\sigma (X)=\sqrt{V(X)}=\sqrt{0.48}=0.693

Thus, the variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

Now compute the variance of (20 - X) as follows:

V(20-X)=V(20)+V(X)-2Cov(20,X)=0+0.48-0=0.48

Compute the standard deviation of (20 - X) as follows:

\sigma (20-X)=\sqrt{V(20-X)} =\sqrt{0.48}0.693

Thus, the variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

3 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!
Rashid [163]

x =  \frac{ -2 \pm \:  \sqrt{ {2}^{2} - 4 \times 1 \times 10 }  }{2}  \\  \\ x =  \frac{ - 2 \pm 6i}{2}  \\  \\  \boxed{ \red{ \huge{x =  - 1 \pm \: 3i}}}

\boxed{ \red{ \huge{answer = d}}}
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3 years ago
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