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ratelena [41]
3 years ago
10

Kathy is a repair technician for a phone company. Each week, she receives a batch of phones that need repairs. The number of pho

nes that she has left to fix at the end of each day can be estimated with the equation P=108−23d P = 108 − 23 d , where P is the number of phones left and d is the number of days she has worked that week. What is the meaning of the value 108 in this equation?
Mathematics
1 answer:
Semenov [28]3 years ago
7 0

Answer:

What 108 represents here is that the total number of phones she has to fix each week is 108 phones

Step-by-step explanation:

The linear equation is

P = 108-23d

compare this with the general form;

y = mx + c

we have;

P = -23d + 108

We can see that 108 represents the y-intercept in this case

The x-value at the y-intercept is 0

So what this mean is that the number of phones she has to fix each week is 108

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earnstyle [38]

Answer:

1. (x,y)→(y,-x)

2. (x,y)→(-y,x)

3. (x,y)→(-x,-y)

Step-by-step explanation:

1. Rotation 90° clockwise (or 270° counterclockwise) about the origin changes x into y and y into -x, so it has the rule

(x,y)→(y,-x)

2.  Rotation 90° counterclockwise (or 270° clockwise) about the origin changes x into -y and y into x, so it has the rule

(x,y)→(-y,x)

3.  Rotation 180° clockwise  about the origin changes x into y and y into -x, so it has the rule

(x,y)→(-x,-y)

Here you can apply rotation by 90° clockwise twice, so

(x,y)→(-y,x)→(-x,-y)

3 0
3 years ago
What is the value of the expression 9+n/3-6 when n is 12?
Nina [5.8K]
-7 (9+12/3-6)=21/-3=-7
4 0
3 years ago
Read 2 more answers
4n + 8 = 20
Serggg [28]

Answer:

The answer is 3

Step-by-step explanation:

4 x 3 = 12

8 + 12 = 20

5 0
3 years ago
Read 2 more answers
5p-9=2p+12<br><br><br> Please help!!!
Luba_88 [7]
5p-9=2p+12
   +9       +9
 5p= 2p+21
-2p -2p
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4 0
3 years ago
Read 2 more answers
Determine whether the given function is a solution to the given differential equation.
lesantik [10]

Given :

A function , x = 2cos t -3sin t               .....equation 1.

A differential equation , x'' + x = 0      .....equation 2.

To Find :

Whether the given function is a solution to the given differential equation.

Solution :

First derivative of x :

x'=\dfrac{d(2cos t - 3sin t)}{dt}\\\\x'=\dfrac{d(2cost)}{dt}-\dfrac{(3sint)}{dt}\\\\x'=-2sint-3cost

Now , second derivative :

x''=\dfrac{d(-2sint-3cost)}{dt}\\\\x''=-\dfrac{d(2sint)}{dt}-\dfrac{d(3cost)}{dt}\\\\x''=-2cost+3sint

( Note : derivative of sin t is cos t and cos t is -sin t )

Putting value of x'' and x in equation 2 , we get :

=(-2cos t + 3sin t ) + ( 2cos t -3sin t )

= 0

So , x'' and x satisfy equation 2.

Therefore , x function is a solution of given differential equation .

Hence , this is the required solution .

8 0
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