Consider the coordinate plane:
1. The origin is the point where Sharon and Jacob started - (0,0).
2. North - positive y-direction, south - negetive y-direction.
3. East - positive x-direction, west - negative x-direction.
Then,
- if Jacob walked 3 m north and then 4 m west, the point where he is now has coordinates (-4,3);
- if Sharon walked 5 m south and 12 m east, the point where she is now has coordinates (12,-5).
The distance between two points with coordinates
and
can be calculated using formula

Therefore, the distance between Jacob and Sharon is

I've attached the graphs to this answer. I hope they help.
Answer:
B)
B)
D)
Step-by-step explanation:
1.
The GCF of all the term of the above polynomial is
, hence we take it outside and form a bracket
The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer
2.
The GCF of all the term of the above polynomial is
, hence we take it outside and form a bracket
The polynomial within the bracket can not be factorized further hence this is our final answer. Option (B) is the right answer
3. 
The GCF of all the term of the above polynomial is
, hence we take it outside and form a bracket
The polynomial within the bracket can not be factorized further hence this is our final answer. Option (D) is the right answer
Answer: A = 20
How to Solve:
Just by looking at this problem I can tell that the denominators (9 an 45) are factors of 9. So the second equation is multiplied by 5 from the first equation.
4/9 x 5
4 x 5 = 20
— -—
9 x 5 = 45
So A would be 20.
Another way to solve this would be by multiplying the 1st equations numerator with the second equations denominator:
4 x 45 = 180
Then divide 180 with the 1st equation’s denominator.
180 / 9 = 20
A = 20
Complete theh square
isolate x terms
factor out coefient of x^2 term
take 1/2 of 1st degree coefient and square it, add positive and negative inside parnthasees, expand
f(x)=(2x^2+12x)+7
f(x)=2(x^2+6x)+7
6/2=3, 3^2=9
f(x)=2(x^2+6x+9-9)+7
f(x)=2((x+3)^2-9)+7
f(x)=2(x+3)^2-19+7
f(x)=2(x+3)^2-12