You can write three equations in the numbers of nickels (n), dime (d), and quarters (q).
n + d + q = 23 . . . . . . . there are 23 coins total
0n +d -q = 2 . . . . . . . . .there are 2 more dimes than quarters
5n +10d +25q = 250 . .the total value is $2.50
The collection includes 11 nickels, 7 dimes, and 5 quarters.
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I used the matrix function of my calculator to solve these equations. You can find q by subtracting from the last equation five times the sum of the first two equations.
(5n +10d +25q) -5((n +d +q) +(d -q)) = (250) -5(23 +2)
25q = 125 . . . . . . . simplify
q = 5
From the second equation,
d = q +2 = 7
And from the first,
n = 23 -5 -7 = 11
Probability=(number of specific outcomes)/(total number of possible outcomes)
P(!Z)=25/26 as a fraction exact
P(!Z)≈96.2% (approximation to nearest tenth of a percent)
Answer:
<h3>Negative one-half (negative 2) (x + 3) = negative 10 (negative one-half)</h3>
Step-by-step explanation:
Given the expression
- 2 (x + 3) = - 10
The first step in solving the expression is to multiply both sides by -1/2 as shown;
-1/2(-2)(x+3) = -1/2(-10)
(x +3) = 1/2(10)
x + 3 = 5
x = 5-3
x = 2
Hence the correct option is Negative one-half (negative 2) (x + 3) = negative 10 (negative one-half)
