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2 years ago

Factor completely 9-6a-24a^2

2 answers:

7 0

-24a²- 6a +9 = - 3(8a² +6a - 9)

8a² +6a - 9 =0

x=(-b +/-√(b² - 4ac))/2a
x = (-6 +/-√(36+4*8*9) /(2*8) = (-6 +/-√(324)  /16 =  (-6 +/-18)/16
x1 =  (-6 +18)/16 = 0.75
x2 =  (-6 -18)/16 = - 1.5

-24a²- 6a +9 = - 3(8a² +6a - 9) = -3(a - 0.75)(a + 1.5)

sineoko [7]2 years ago

4 0

-3 (2a - 1) (4a + 3)

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2 years ago

What is the value of x6+y2 when x equals 1 and y equals 11

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Answer:

Step-by-step explanation:

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6 0

2 years ago

8x^3-8x=1<br> Solve for x

Anit [1.1K]

Step-by-step explanation:

Step-by-step explanation:

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2 years ago

Select all the roots of the following equation.

strojnjashka [21]

Answer:

5, -9

Step-by-step explanation:

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6 0

2 years ago

Read 2 more answers

Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)

Leni [432]

Alrighty

remember some rules
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}=\frac{1}{x^m}$
and
$x^0=1$ for all real values of x
and
$(a^b)^c=a^{bc}$
and
$(\frac{a}{b})^c=\frac{a^c}{b^c}$
and
(a/b)/(c/d)=(ad)/(bc)
and
$(a^b)(a^c)=a^{b+c}$
and
$\frac{a^m}{a^n}=a^{m-n}$
and don't forget pemdas
example: $-x^m=-1(x^m)$ but $(-x)^m=(-1)^m(x^m)$

so

4.
$(\frac{c^{-2}}{2})^{-2}=$

$\frac{(c^{-2})^{-2}}{2^{-2}}=$

$\frac{c^4}{\frac{1}{2^2}}=$

$\frac{c^4}{\frac{1}{4}}=$

$4c^4$

5.

$\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=$

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$\frac{-a^4b^4c^5}{a^2}=$

$-a^2b^4c^5$

3 0

2 years ago