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Marina86 [1]
3 years ago
9

Need help ASAP like please

Mathematics
1 answer:
kenny6666 [7]3 years ago
4 0

Answer:

what is this bro .................

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Find the measure of arc DF
givi [52]

Answer:

Step-by-step explanation:

Angle E is one-half the measure of the difference between arc CG and arc DF. Mathematically, that looks like this:

44=\frac{1}{2}(160-DF) and

44(2) = 160 - DF and

88 = 160 - DF and

-72 = -DF so

DF = 72 degrees, second choice down

7 0
3 years ago
What is the greatest common factor of 35b^2, 15b^3, and 5b?
hammer [34]

Answer:

The first expression can be rewritten as

35 {b}^{2} = 5 \times 7 \times {b}^{2}35b

2

=5×7×b

2

The second expression is rewritten as

15 {b}^{3} = 3 \times 5 {b}^{3}15b

3

=3×5b

3

The third expression is

5b = 5 \times b5b=5×b

The greatest common factor is the product of the least powers of the common factors.

4 0
3 years ago
Read 2 more answers
For each function f(n) and time t in the table, determine the largest size n of a problem that can be solved in time t, assuming
egoroff_w [7]
First recall that a microsecond is 10^−6 seconds. Hence, one second = 10^6 microseconds, one hour = 3600000000 = 3.6 • 10^9 microseconds, one month (assume a month has 30 days) = 2592000000000 = 2.592 • 10^12 microseconds, and one century = 3110400000000000 = 3.1104 • 10^15 microseconds.

Row 1: f(n) = log n In this case, we need to determine the largest n such that log n ≤ 1000000. To solve this inequality, we need to rewrite the inequality as 2^logn ≤ 2^1000000 or n ≤ 2^1000000. Recall from lecture that 2^10 ≈ 10^3, thus we have that 2^1000000 = 2^10•100000 = (2^10)^100000 ≈ (10^3)^100000 = 10^300000. This is the result given in the textbook. For one hour, we have that n ≤ 2^3600•1000000 and thus n ≈ 10^1080000000.

Row 8: f(n) = n! For us to see that the largest sized input is 12 that can be processed within an hour when f(n) = n! one can simply, compute 12! And verify that it is less than the number of microseconds in one hour, but that 13! is greater than the number of microseconds in an hour.

Row 4: f(n) = n log n In this case, use Maple to solve equations like n log n−1000000 = 0. The Maple command for solving this equation is fsolve(n*log[2](n) - 1000000 = 0)
8 0
4 years ago
A skydiver is falling at about 176 per second how many feet per minute is he falling
garik1379 [7]

Answer:

the answer is 10,560 feet per minute

Step-by-step explanation:

(176* 60 seconds) / (1 second* 1 minute)

8 0
3 years ago
What is the area of the pentagon, rounded to the nearest tenth?
Rudik [331]

The area of the pentagon, rounded to the nearest tenth will be 32.7 square cm. Then the correct option is C.

<h3>What is a polygon?</h3>

The polygon is a 2D geometry that has a finite number of sides. And all the sides of the polygon are straight lines connected to each other side by side.

A regular pentagon has an apothem measuring 3 cm and a perimeter of 21.8 cm.

Then the side length of the pentagon will be

5 x Side length = 21.8 cm

     Side length = 4.36 cm

Then the area of the pentagon, rounded to the nearest tenth will be

Area of pentagon = 5 x area of triangle

Area of pentagon = 5 x 1/2 x 4.36 x 3

Area of pentagon = 32.7 square cm

Thus, the correct option is C.

More about the polygon link is given below.

brainly.com/question/17756657

#SPJ1

4 0
3 years ago
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