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2 answers:
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Answer:
A = 20sinθ(6 + 5 cosθ) cm²
Step-by-step explanation:
Drop perpendiculars DE and CF to AB.
Then, we have congruent triangles ADE and BCF, plus the rectangle CDEF.
The formula for the area of the trapezium is
A = ½(a + b)h
DE = 10sinθ
AE = 10cosθ
BF = 10cosθ
EF = CD = 12 cm
AB = AE + EF + BF = 10cosθ + 12 + 10 cosθ = 12 + 20cosθ
A = ½(a + b)h
= ½(12 +12 + 20 cosθ) × 10 sinθ
=(24 + 20 cosθ) × 5 sinθ
= 4(6 + 5cosθ) × 5sinθ
= 20sinθ(6 + 5 cosθ) cm²
Answer:
Step-by-step explanation:
To write a circle in standard form, expand the equation of the circle and move all terms to one side.
Step-by-step explanation:
pythogoras theorem = Q²=P²+R²
P=P
Q= 57.6
R=33.8 =
(57.8)²=(P)²+(33.8)²
=3,340.84=(P)²+1142.44
=3340.84-1142.44=P²
=2,198.4=P²