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aleksandrvk [35]
3 years ago
6

Write out the form of the partial fraction decomposition of the function (as in this example). do not determine the numerical va

lues of the coefficients. (a) x4 − 2x3 + x2 + 7x − 5 x2 − 2x + 1 x2− a x−1​− b (x−1)2​ (b) x2 − 1 x3 + x2 + x
Mathematics
1 answer:
neonofarm [45]3 years ago
7 0
\frac{x^{4}-2x^{3}+x^{2}+7x-5}{x^{2}-2x+1} = x^{2}+\frac{a}{x-1}+\frac{b}{(x-1)^{2}}
It looks like your first selection (a) is appropriate.
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romanna [79]
*******************************************************
(See attached formula)
Loan Principal = 104,000 - 24,000 = 80,000
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Monthly Payment = <span> <span> 0.0070833333 </span> + </span><span> <span> [ 0.0070833333 / ((1</span></span><span>.0070833333)^300 -1)) ] *principal
</span>
Monthly Payment = <span>0.0070833333 + </span><span> [ 0.0070833333 / (</span><span> </span> <span> <span> <span> 8.3104129461 </span> </span> </span> -1)] * 80,000
Monthly Payment = 0.0070833333 + [ 0.0070833333 / ( 7.3104129461)] * 80,000
Monthly Payment = (0.0070833333 + <span> <span> <span> 0.00096893750767) * 80,000
</span></span></span>Monthly Payment = <span> <span> <span> 0.00805227080767 </span> </span> </span> * 80,000
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Source:
http://www.1728.org/calcloan.htm

</span></span></span>

3 0
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If the simple interest on ​$2000 for 3 years is ​$​300, then what is the interest​ rate?
ivann1987 [24]

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill &\$300\\ P=\textit{original amount deposited}\dotfill & \$2000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &3 \end{cases} \\\\\\ 300=(2000)(r)(3)\implies 300=6000r\implies \cfrac{300}{6000}=r \\\\\\ \cfrac{1}{20}=r\implies 0.05=r\implies \stackrel{\textit{converting to percent}}{100\cdot 0.05}\implies \stackrel{\%}{5}=r

6 0
3 years ago
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