I don't know the answer but my tip would be to split the shape the way I did it, find the lengths of each side, and then find the area for each individual shape.
Then add all the areas together.
SOMEONE PLEASE HELP ME IM DESPERATE!!
2 answers:
You might be interested in
Answer:
4x + 6
Step-by-step explanation:
To determine what the numerator would be, after simplifying both fractions, take the following steps:
Step 1: Factorise the denominator of the first fraction, x² + 3x + 2.
Thus,
x² + 2x + x + 2
(x² + 2x) + (x + 2)
x(x + 2) +1(x + 2)
(x + 1)(x + 2)
We would now have the following as our new fractions to add together and simplify:
Step 2: find the highest common factor of the denominator of both fractions.
Highest common factor of (x + 1)(x + 2) and (x + 1) = (x + 1)(x + 2)
Step 3: To add both fractions, divide the highest common factor gotten in step 2 by each denominator, and then multiply the result by the numerator of each fraction.
Thus,
Therefore, the numerator of the simplified form sum of both fractions = 4x + 6
something noteworthy is that the independent and squared variable in this case will be the "x", namely the graph of that quadratic is a vertical parabola.
so the parabola has solutions at x = -2 and x = 4, and its vertex will be half-way between those two guys, namely at x = 1.
since this is a vertical parabola, its axis of symmetry, the line that splits its into twin sides, will be a vertical line, and it'll be the x-coordinate of the vertex, since the vertex hasa a coordinate of x = 1, then the axis of symmetry is the vertical line of x = 1.
The probability of getting exactly zero tails is 1/8.
Step-by-step explanation:
When a fair coin is tossed three time, the set of equally likely outcomes is:
S= {HHH,HHT, HTH, THH, HTT, THT, TTH, TTT}
n(S)=8
Let A be the event that there are exactly zero tails which means there are all heads
Then
A= {HHH}
n(A)=1
The probability of getting exactly zero tails is 1/8.
Keywords: Probability, Equally likely events
Learn more about probability at:
#LearnwithBrainly