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s2008m [1.1K]
3 years ago
7

Quadrilateral PQRS is inscribed in a circle, as shown. Which statement is true?

Mathematics
2 answers:
Valentin [98]3 years ago
4 0
The answer is C 

P is half of QRS 
R is half of SPQ
<span>so angles P and R are complementary.</span>
Akimi4 [234]3 years ago
4 0

Answer:

(c)

Step-by-step explanation:

Since the quadrilateral is inscribed in the circle, then by the conjecture property, the opposite angles of the quadrilateral are supplementary and the measure of one angle is equal to half of the measure of the  opposite angle.

Hence, in this case,

∠P= 1/2(arc QRS),

∠R=1/2(arc SPQ)

and ∠P+∠R=180°

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Answer:

35

Step-by-step explanation:

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The daily production goal for the assembly team is 1000 units. They achieved 87% of their goal today. How many units did the ass
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They assembled 870 units
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3 years ago
The weight of turkeys is normally distributed with a mean of 22 pounds and a standard deviation of 5 pounds. a. Find the probabi
Masja [62]

Answer:

a. 0.443

b. 0.023

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The weight of turkeys is normally distributed with a mean of 22 pounds and a standard deviation of 5 pounds.

This means that \mu = 22, \sigma = 5

a. Find the probability that a randomly selected turkey weighs between 20 and 26 pounds.

This is the pvalue of Z when X = 26 subtracted by the pvalue of Z when X = 20. So

X = 26

Z = \frac{X - \mu}{\sigma}

Z = \frac{26 - 22}{5}

Z = 0.8

Z = 0.8 has a pvalue of 0.788

X = 20

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 22}{5}

Z = -0.4

Z = -0.4 has a pvalue of 0.345

0.788 - 0.345 = 0.443

The answer is 0.443

b. Find the probability that a randomly selected turkey weighs below 12 pounds.

This is the pvalue of Z when X = 12. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{12 - 22}{5}

Z = -2

Z = -2 has a pvalue of 0.023

The answer is 0.023.

8 0
3 years ago
A different bicycle is advertised as 30% off of the original price. After the discount, the tax is $28.35
Ilya [14]

Answer:

$160.50

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30% of 439 + 28.35

6 0
3 years ago
Galena is solving the following system. 3x+2y+3z =5 7x+y +7z=-1 4x-4y-z=-3
babymother [125]

Answer:

She did not multiply equation 3 in step 2 by the correct value.

Step-by-step explanation:

Given:

3x+2y+3z=5\\7x+y+7z=-1\\4x-4y-z=-3

In order to solve this, we need to eliminate any one variable and then form a simultaneous equation with the remaining two variables. Then, we nee to solve the simultaneous equation.

Here, Galena is trying to eliminate the variable z first.

Step 1:  She multiplies equation (3) by 3 and adds it to equation (1)

Let us multiply equation (3) by 3

(4x-4y-z=-3)\times 3 = (3\times 4x)-(3\times 4y)-(3\times z)=3\times -3\\(4x-4y-z=-3)\times 3 =12x-12y-3z=-9

Now, adding this to equation 1 will cancel out z terms.

12x-12y-3z+3x+2y+3z=-9+5\\(12x+3x)+(-12y+2y)+(3z-3z)=-4\\15x-10y+0=-4

Now, she need to make one more equation in x\ and \ y.

Step 2: She multiplies equation (3) by -7 and adds it to equation (2)

Multiplying equation (3) by -7 will give,

(4x-4y-z=-3)\times -7 = (-7\times 4x)-(-7\times 4y)-(-7\times z)=-7\times -3\\(4x-4y-z=-3)\times 3 =-28x+28y+7z=21

Now, adding this to equation 2 will not cancel out z terms.

-28x+28y+7z+7x+y+7z=21-1\\(-28x+7x)+(28y+y)+(7z+7z)=20\\-21x+29y+14z=20

So, she makes mistake in step 2 as the z terms are not being cancelled.

6 0
4 years ago
Read 2 more answers
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