Answer:
The price of pretzels in 1975 = $1.80
Step-by-step explanation:
To answer this question we are assuming the steady rate means linear.Let x be the year and y be the price.
We need to find the slope
m = (y2-y1)/(x2-x1)
= (4.80-4.05)/(2015-2005)
=.75/10
= .075
The slope is .075
We can use the point slope form of the equation
y-y1 = m(x-x1)
y-4.80 = .075(x-2015)
Distribute
y - 4.80 = .075x -151.125
Add 4.80 to each side
y - 4.80+4.80 = .075x -151.125+4.80
y = .075 x - 146.325
We want to find out how much pretzels were in 1975. Put in x=1975
y = .075(1975) -146.325
y = 148.125-146.325
y=1.80
Answer:
142
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>The first equation:</u>
<u>The second equation:</u>
<u>Convert to slope-intercept form:</u>
- x + 2y = 23 ⇒ 2y = -x + 23 ⇒ y = -1/2x + 11.5
- 2x + 3y = 39 ⇒ 3y = -2x + 39 ⇒ y = -2/3x + 13
<em>The graph is attached</em>
<u>Intersection point is (9, 7)</u>
- Adult tickets cost $9
- Child tickets cost $7