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levacccp [35]
2 years ago
10

Which of these describe a scenario in which the given quantity changes at a constant rate with respect to time? Select

Mathematics
1 answer:
ehidna [41]2 years ago
4 0

Answer: A,B

Step-by-step explanation: the numbers constantly add up only by 218 or 1240 , C and D would not be correct because the rate of change increases as will with the total sum after each period of time

also tiny hint, if you were to draw an X,Y axis graph, A and B would be a straight line while C and D are curved up-wards

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Write a phrase as an algebraic expression six less than a number times 11
nadezda [96]

Let the number = x

11x is 11 times the number.  You are to take 6 less than this. Be careful how you read six less. It means the 6 is subtracted from the 11x

11x - 6 This is what you finally get.


7 0
2 years ago
3. Which rule best describes the last three numbers shown in the pattern? 10, 12, 9, 11​
sergij07 [2.7K]

Answer:

it goes by 2 two times then subtracts 3 then again

Step-by-step explanation:

10,12,9,11,8,10,7

5 0
3 years ago
Can you help me please ​
alexira [117]

Answer:

Please check the explanation.

Step-by-step explanation:

Given that

|v|=38

Ф = 120°

<u>Finding the horizontal component</u>

The horizontal component can be obtained using the formula

Vx = |v| cos Ф

     = 38 cos 120°

     = 38 (-0.5)

      = -19

Thus, the  horizontal component is:

Vx = -19

<u>Finding the vertical component</u>

The vertical component can be obtained using the formula

Vy = |v| sin Ф

    = 38 sin 120°

    = 38 (0.86)

    = 32.68

Thus, the vertical component is:

Vy = -19

  • A vector 'v' with magnitude |v| and direction Ф can be written as:

v = |v| cos Ф i + |v| sin Ф j

As

|v|=38

Ф = 120°

Thus, the vector is

v = 38 cos 120° i + 38 sin 120° j

or

v = -19 i + 32.68 j

5 0
2 years ago
Mrs. Smith had the following transactions during the week:
blsea [12.9K]

Answer:

fghffjfghxhhg

56

Step-by-step explanation:

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8 0
3 years ago
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Simply<br> 7p2 x 3p<br> 14p4
vivado [14]

Answer:

{ \tt{ =  \frac{7 {p}^{2}  \times 3p}{14 {p}^{4} } }} \\  = { \tt{ \frac{21 {p}^{3} }{14 {p}^{4} } }} \\  = { \tt{1.5 {p}^{ - 1} }}

6 0
2 years ago
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