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2 years ago

Find the theoretical probability. Simplify completely.

Mathematics

2 answers:

mart [117]2 years ago

6 0

Answer: 1/2

Explanation:

There are 8 number in the set

And 4 of them are even

We can write it
P(even) = 4/8 = 1/2

qwelly [4]2 years ago

3 0

Answer:

1/2

Step-by-step explanation:

Total outcome is 8

Favorable outcome is 4

P( 2, 4, 6, or 8) = 4/8 = $\frac{1}{2}$

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True or False? The segment AB is congruent to the segment BC. A. True B. False

AleksAgata [21]

Answer:

True

Step-by-step explanation:

If O to the edge of the circle is the radius and if B is on the radius line and has a right angle, then B is the halfway point.

3 0

2 years ago

Select all that apply:

avanturin [10]

Answer: (-6,-4) (-2,-2) (-1,0) (2,6)

Step-by-step explanation:

We can see that points (2,0) and (4,1) isn't plotted on the line

3 0

2 years ago

What is the length of the unknown

AVprozaik [17]

The answer is A.

Explanation:

Since this is a right triangle you can use The formula: leg squared plus leg squared = hypotenuse squared

So lets square the hypotenuse and first leg
And you get 85 hypotenuse and 49 leg

So just subtract 49 from 85 to get the other leg squares

You get 36 so now just square root it

Square root of 36 is 6

So the best answer is 6

Hope this helps some.

8 0

3 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.

konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

$BC^2=BD\cdot AB.$

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

$x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.$

Take positive value x. You get

$AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.$

2. According to the previous theorem,

$AC^2=AD\cdot AB.$

Then

$AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

Answer: $AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

$CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D$

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0

3 years ago

Read 2 more answers

The tables below show running hours of three printers that produce greeting cards and the total number of greeting cards produce

AysviL [449]

ANSWER

The correct answer is A

EXPLANATION

To find the ink cost of each card coming from printer B, we need to find the total cost from printer B and the total number of cards printed by Printer B.

The total hours of all the three printers over the three weeks

$=40+45+55+50+50+30+45+40+60=415$