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Vladimir [108]
3 years ago
7

Solve. 2x + 6 - 7x = 21

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0
-7x + 2x (add common factors)
-5x+6+21 (what happen to one side happens to the others
-5x=21 (divide by five)
x= -3
Naddika [18.5K]3 years ago
5 0
Combine like terms, 2x + -7x = -5x.
Now you have -5x + 6 = 21.
subtract 6 from both 6 and 21, the 6 cancels out and 21-6=15.
You’re left with -5x=15
Divide 5 on both sides, -5 cancels out, and you’re left with
x=-3
sorry this was messy and i hope this made sense!
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mrs_skeptik [129]

Answer:

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Step-by-step explanation:

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3 years ago
Eight minus the product of two and a number x.
sergij07 [2.7K]
The number x is a -8
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3 years ago
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7 0
3 years ago
Find the generating function for the sequence 1,-2,4,-8, 16, ...
kirill [66]

Answer:

  a(x)=\dfrac{1}{1+2x}

Step-by-step explanation:

The generating function a(x) produces a power series ...

  a(x)=a_0+a_1x+a_2x^2+a_3x^3+\dots

where the coefficients are the elements of the given sequence.

We observe that the given sequence has the recurrence relation ...

  a_0=1;a_n=-2a_{n-1} \quad\text{for n $>$ 0}

This can be rearranged to ...

  a_n+2a_{n-1}=0

We can formulate this in terms of a(x) as follows, then solve for a(x).

\sum\limits^{\infty}_{n=1} {a_{n}x^n} =a(x)-a_0 \quad\text{and}\\\\\sum\limits^{\infty}_{n=1} {2a_{n-1}x^n} =(2x)a(x) \quad\text{so}\\\\\sum\limits^{\infty}_{n=1} {(a_n+2a_{n-1})x^n}=0=a(x)-a_0+2xa(x)\\\\a(x)=\dfrac{a_0}{1+2x}=\dfrac{1}{1+2x}

The generating function is ...

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3 0
3 years ago
Read 2 more answers
Use integration by parts to find the integrals in Exercise.<br> ∫(4x-12)e-8x dx.
stepladder [879]

Answer:

e(2x^{2} -12x)-4x^{2}+C

Step-by-step explanation:

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Let us solve our given problem.

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Take out constant:

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e(\frac{4x^{1+1}}{2} -12x)-8*\frac{x^{1+1}}{1+1}+C

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Therefore, our required integral would be e(2x^{2} -12x)-4x^{2}+C.

5 0
3 years ago
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