Answer: 19
Step-by-step explanation:
Answer:

Step-by-step explanation:
Start by factoring out a -1...

Now, we have to find two integers that multiply to get -16 and have a sum of 6:
(-2)*8=-16
-2+8=8-2=6
Using this, we can split 6x into -2x and 8x...

Factor the first and second half separately...
![f(x)=-[(x^2-2x)+(8x-16)]\\f(x)=-[x(x-2)+8(x-2)]\\](https://tex.z-dn.net/?f=f%28x%29%3D-%5B%28x%5E2-2x%29%2B%288x-16%29%5D%5C%5Cf%28x%29%3D-%5Bx%28x-2%29%2B8%28x-2%29%5D%5C%5C)
Since both x and 8 are being multiplied by x-2, we can combine them to get...

Answer:
+
*LN(|
|) +C
Step-by-step explanation:
we will have to do a trig sub for this
use x=a*tanθ for sqrt(x^2 +a^2) where a=2
x=2tanθ, dx= 2 sec^2 (θ) dθ
this turns
into integral(sqrt( [2tanθ]^2 +4) * 2sec^2 (θ) )dθ
the sqrt( [2tanθ]^2 +4) will condense into 2sec^2 (θ) after converting tan^2(θ) into sec^2(θ) -1
then it simplifies into integral(4*sec^3 (θ)) dθ
you will need to do integration by parts to work out the integral of sec^3(θ) but it will turn into (1/2)sec(θ)tan(θ) + (1/2) LN(|sec(θ)+tan(θ)|) +C
then you will need to rework your functions of θ back into functions of x
tanθ will resolve back into
(see substitutions) while secθ will resolve into
sec(θ)=
is from its ratio identity of hyp/adj where the hyp. is
and adj is 2 (see tan(θ) ratio)
after resolving back into functions of x, substitute ratios for trig functions:
=
+
*LN(|
|) +C
first you need to mulitply 13 x 3 which is 39, then subtract 2 which is 37.
Answer: City needs 2.4 inches of rainfall more to match the record of 40 inches.
Step-by-step explanation:
Since we have given that
Total annual rainfall a city record = 40 inches
This year, total rainfall recorded = 37.6 inches
Number of inches of rainfall is needed to match the record of 40 inches is given by

Hence, City needs 2.4 inches of rainfall more to match the record of 40 inches.