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Andrews [41]
3 years ago
9

What is the half of 14.5

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
6 0

14.5/2=7.25

if it asks for half then its telling you to divide it by 2

Aleks04 [339]3 years ago
3 0

Answer:

7.25

Explanation:

14.5×½=7.25

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Name a fraction is equivalent to 7/2
attashe74 [19]

Answer:

14/4

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The largest jaw breaker in a store is spherical with a radius of 2 in, and sells for $4.00. A
maw [93]

Answer:

$36

Step-by-step explanation:

1. Determine the surface area of the  largest jaw breaker

Surface area of a sphere = 4πr²

4 x 3.14 x 2² = 50.24in²

2. Determine the surface area of the new jaw breaker

4 x 3.14 x 6² = 452.16 in²

3. Determine the cost per area

4/ 50.24

4. Determine the price for the new jaw breaker

4/ 50.24 x 452.16 = $36

5 0
2 years ago
Verify identity list steps. Cot(t)(1-cos^2(t))=cos(t)sin(t)
storchak [24]
Remember: We have to work from either the LHS or the RHS.
(Left hand side or the Right hand side)

You should already know this:

\huge{Cot(t) = \frac{1}{tan(t)} = \frac{1}{\frac{sin(t)}{cos(t)}} = 1\div \frac{sin(t)}{cos(t)} = 1\times \frac{cos(t)}{sin(t)}=\boxed{\frac{cos(t)}{sin(t)}}


You should also know this:

sin^2(t) + cos^2(t) = 1\\\\\boxed{sin^2(t)} = 1 - cos^2(t)

So plugging in both of those into our identity, we get:

\frac{cos(t)}{sin(t)}\cdot sin^2(t) = cos(t)\cdot sin(t)

Simplify the denominator on the LHS (Left Hand Side)

We get:

cos(t) \cdot sin(t) = cos(t) \cdot sin(t)

LHS = RHS

Therefore, identity is verified.
4 0
3 years ago
Plsss help meee in math :(((​
pishuonlain [190]

Answer:

a = 30

2a = 60

3a = 90

Step-by-step explanation:

3a + 2a + a = 180 ( Sum of angles of a triangle is 180)

6a = 180

a = 180/6

a = 30

2a = 2 x 30 =60

3a = 3 x 30 = 90

6 0
3 years ago
What is the area of the parallelogram?
Maksim231197 [3]

Answer:

Step 1: area is base × height

Step 2: 36cm2

Step-by-step explanation:

Base × height is 9 and 4 and 9×4 = 36cm2

Hope this helps :)

8 0
1 year ago
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