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Andrews [41]
3 years ago
9

What is the half of 14.5

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
6 0

14.5/2=7.25

if it asks for half then its telling you to divide it by 2

Aleks04 [339]3 years ago
3 0

Answer:

7.25

Explanation:

14.5×½=7.25

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A retailer who sells backpacks estimates that by selling them for x dollars each, she will be able to sell 100−x backpacks each
zvonat [6]

Answer:

x = 50

R = $2500

Step-by-step explanation:

Given in the question a quadratic equation,

−x² + 100x

To find the selling price, x, which will give highest revenue, y, we will find maximum value of parabola curve −x² + 100x

The value of -b/2a tells you the value x of the vertex of the function

−x² + 100x

here a = -1

        b = 100

Selling price = -(100)/2(-1)

                    =   50

 

R = −(50)² + 100(50)

  = 2500

8 0
4 years ago
What is the equation of a line with slope -3 through the point (3, 5)?
patriot [66]

Answer:

y = -3x + 5

Step-by-step explanation:

4 0
2 years ago
Plz help<br> Will mark brainliest
Alexandra [31]

Answer:

(0,-1)

Step-by-step explanation:

(0,-1) will work because when you plug them is it is equivalent to 4

6 0
3 years ago
3. A piece of white oak has a densityof 0.77 g/cm and a mass of 100 g,what would be the volume of thesample? PLEASE HELP!
Nezavi [6.7K]
\text{Volume}=129.87cm^3

Explanation

Step 1

the density of an object is given by:

\text{density}=\text{ }\frac{mass}{\text{volume}}

Step 2

let

\begin{gathered} \text{density}=0.77\frac{g}{cm^3} \\ \text{mass}=\text{ 100 g} \\  \end{gathered}

Step 3

replace,

\begin{gathered} \text{density}=\text{ }\frac{mass}{\text{volume}} \\ 0.77\frac{g}{cm^3}=\frac{100g}{\text{volume}} \\ \text{volume}\cdot0.77\frac{g}{cm^3}=\text{1}00\text{ g} \\  \\ \text{Volume}=\frac{100\text{ g}}{0.77\frac{g}{cm^3}} \\ \text{Volume}=129.87cm^3 \end{gathered}

I hope this helps you

5 0
1 year ago
What is the value of d to the nearest tenth
Gelneren [198K]
The answer is 72.1.you should dot infront sizes and then equals them
6 0
3 years ago
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