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natali 33 [55]
3 years ago
7

In a WHS P.E. class, if Team A scores 5 touchdowns , 3 two point baskets, 1 three point baskets, 10 team handball goals, and 7 s

occer goals while Team B scores 3 touchdowns, 7 two point baskets, 10 three point baskets, 5 team handball goals and 9 soccer goals... What is the combined score ? Please help
Mathematics
1 answer:
Jlenok [28]3 years ago
3 0

Answer

<h2><u>Team A  </u>                           <u>Team B</u></h2>

6 points -basketball                               21 points - football

3 points -basketball                               14 points - basketball

10 points -handball                                30 points - basketball

07 points - soccer                                  05 points - handball

<u>                                 </u>                               09 points - soccer

<em><u>26 points total </u></em><em>                                    </em><u><em>                                           </em></u>

<em>                                                                </em><u><em> 79 points total  </em></u>

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Classify the following triangle. Check all that apply.
klasskru [66]

Answer:

Step-by-step explanation:

a. scalene  :  Reason: all angles and sides are different measurements.

f. acute : all the three angles are acute (Less than 90)

5 0
3 years ago
Read 2 more answers
the ratio of keiths age to Jared's ages 3 to 5 if Keith is 24 years old how old is Jared please show how many you got this answe
pishuonlain [190]
Comment
You need to set up a direct proportion. You have to relate Keith and Jared's ages to the ratio you were given.

Givens
Keith is 24
Keith / Jared = 3/5
J = Jared 

Solution
3/5 = 24 / J Cross multiply
3*J = 5 * 24 Combine factors on the right.
3J = 120     Divide by 3
J = 120 / 3
J = 40

Conclusion
Jared is 40 years old.
4 0
3 years ago
Convert 0.7135° to minutes and seconds. Round to the nearest second.
jarptica [38.1K]
0° 42' 48.6". 
Conversion: 
d = int(.7135°) = 0°m = int((.7135° - 0°) × 60) = 42's = (.7135° - 0° - 42'/60) × 3600 = 48.6".7135°= 0° 42' 48.6"
How to convert decimal degrees to degrees,minutes,seconds

One degree (°) is equal to 60 minutes (') and equal to 3600 seconds ("):

1° = 60' = 3600"

The integer degrees (d) are equal to the integer part of the decimal degrees (dd):

d = integer(dd)

The minutes (m) are equal to the integer part of the decimal degrees (dd) minus integer degrees (d) times 60:

m = integer((dd - d) × 60)

The seconds (s) are equal to the decimal degrees (dd) minus integer degrees (d) minus minutes (m) divided by 60 times 3600:

s = (dd - d - m/60) × 3600



6 0
3 years ago
6.) ? Need help with the steps
Law Incorporation [45]
Well you equal out the two angles to each other and solve for x. then you just plug the the number you got for x back into the equations to get your answers
3 0
3 years ago
Can someone tell me how
gulaghasi [49]

the way I get the subsequent term, nevermind the exponents, the exponents part is easy, since one is decreasing and another is increasing, but the coefficient, to get it, what I usually do is.

multiply the current coefficient by the exponent of the first-term, and divide that by the exponent of the second-term + 1.

so if my current expanded term is say 7a³b⁴, to get the next coefficient, what I do is (7*3)/5   <----- notice, current coefficient times 3 divided by 4+1.

anyhow, with that out of the way, lemme proceed in this one.

\bf ~~~~~~~~\textit{binomial theorem expansion} \\\\ \qquad \qquad (1+ax)^n\implies \begin{array}{llll} term&coefficient&value\\ \cline{1-3}&\\ 1&+1&(1)^n(ax)^0\\\\ 2&+\frac{(1)(n)}{1}\to n&(1)^{n-1}(ax)^1\\\\ 3&+\frac{n\cdot (n-1)}{2}&(1)^{n-2}(ax)^2 \end{array}

so, following that to get the next coefficient, we get those equivalents as you see there for the 2nd and 3rd terms.

so then, we know that the expanded 2nd term is 24x therefore

\bf n(1)^{n-1}(ax)1 = 24x\implies n(1)(ax)=24x\implies nax=24x\implies n=\cfrac{24}{a}

we also know that the expanded 3rd term is 240x², therefore we can say that

\bf \cfrac{n(n-1)}{2}~~(1)^{n-2}(ax)^2 = 240x^2\implies \cfrac{n(n-1)}{2}(1)(a^2x^2) = 240x^2 \\\\\\ \cfrac{(n^2-n)(a^2x^2)}{2}=240x^2\implies \cfrac{(n^2-n)(a^2)}{2}=\cfrac{240x^2}{x^2}\implies \cfrac{a^2n^2-a^2n}{2}=240 \\\\\\ a^2n^2-a^2n=480

but but but, we know what "n" equals to, recall above, so let's do some quick substitution

\bf a^2n^2-a^2n=480\qquad \boxed{n=\cfrac{24}{a}}\qquad a^2\left( \cfrac{24}{a} \right)^2-a^2\left( \cfrac{24}{a} \right)=480 \\\\\\ a^2\cdot \cfrac{24^2}{a^2}-24a=480\implies 24^2-24a=480\implies 576-24a=480 \\\\\\ -24a=-96\implies a=\cfrac{-96}{-24}\implies \blacktriangleright a = 4\blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ n=\cfrac{24}{a}\implies n=\cfrac{24}{4}\implies \blacktriangleright n=6 \blacktriangleleft

7 0
4 years ago
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