(3c+s)(100-20)/100=100 multiply both sides by 100
(3c+s)80=10000 divide both sides by 80
3c+s=125 subtract 3c from both sides...
s=125-3c....now let's look at the second situation...
(4c+2s)(100-40)/100=120 multiply both sides by 100
60(4c+2s)=12000 divide both sides by 60
4c+2s=200 divide both sides 2
2c+s=100 subtract 2c from both sides
s=100-2c, and from earlier we saw that s=125-3c, since s=s:
100-2c=125-3c add 3c to both sides
100+c=125 subtract 100 from both sides
c=25, and since s=100-2c
s=50
So cds cost $25.00 and sweatshirts cost $50.00
<u>ANSWER</u>
A. (4,12)
<u>EXPLANATION</u>
The equations are:
and
To eliminate a variable we make the coefficients of that variable the same in both equations.
It is easier to eliminate x.
We multiply the first equation by 2 to get:
We add equations (2) and (3).
Divide both sides by 23
Put x=4 into equation (1).
The solution is (4,12)
Answer: 3log5(2) - 1 or ~0,29203
Step-by-step explanation:
2log5(4) - log5(10)
log5(4^2) - log5(10)
log5(4^2/10)
log5(16/10)
log5(8/5)
Log5(8) - log5(5)
log5(2^3) - 1
3log5(2) - 1
3x-10>4+7x-3
3x-10>1+7x
-4x-10>1
-4x>11
x<-11/4
Hope Your Thanksgiving Goes Well, Here's A Turkey
-TheKoolKid1O1
