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9966 [12]
2 years ago
15

Find KL in the image below.

Mathematics
1 answer:
gtnhenbr [62]2 years ago
7 0

Answer:

k\:is \: the \: mid \: opint \: of \:GF

L\:is\:the \:mid\:point\:of GH

KL=1/2(16)

KL=8

<u>OAmalOHopeO</u>

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I REALLY NEED HELP ON THESE TWO QUESTIONS!!! I'd really appreciate it...
Mariana [72]

Answer:

On the first one the total is 37500.The second dealer is again,37500.You put a coma after every 3 digit so the coma is 357,000.Sorry if I over explained it.

6 0
3 years ago
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Y=x^2-2x-1 and y=-3x+5 solved algebraically
eduard

Answer:

Step-by-step explanation:

y=x²-2x-1

and y=-3x+5

x²-2x-1=-3x+5

x²+x-6=0

x²+3x-2x-6=0

x(x+3)-2(x+3)=0

(x+3)(x-2)=0

x=-3,2

when x=-3

y=-3×-3+5=9+5=14

when x=2

y=-3×2+5=-6+5=-1

so solutions are (-3,14) and (2,-1)

3 0
3 years ago
The student council needs to raise at least $950 to pay for their trip to Washington, DC. They have raised $589.55
podryga [215]

Answer:

181 bagels

Step-by-step explanation:

Well how much money did they have to raise more to get to $950? It is $360.45. So now we take $360.45 and divide it by 2 and we get 180.225. But if we round 180.225 they would have to sell at least 181 bagels to raise $950 dollars.

3 0
3 years ago
If u(x) = x5 – x4 + x2 and v(x) = –x2, which expression is equivalent to (u/v)(x)
choli [55]

Answer:

c) -x^3 + x^2 - 1

Step-by-step explanation:

Given: u (x) = x^5 - x^4 +x^2 and v(x) = -x^2

(u/v)(x) = u(x)/v(x)

Now plug in the given functions in the above formula, we get

= (x^5 - x^4 + x^2) / -x^2

We can factorize the numerator.

In x^5 - x^4 + x^2. the common factor is x^2, so we can take it out and write the remaining terms in the parenthesis.

= x^2 (x^3 - x^2 + 1) / - x^2

Now we gave x^2 both in the numerator and in the denominator, we can cancel it out.

(u/v)(x) = (x^3 - x^2 + 1) / -1

When we dividing the numerator by -1, we get

(u/v)(x) = -x^3 + x^2 - 1

Answer: c) -x^3 + x^2 - 1

Hope you will understand the concept.

Thank you.

6 0
3 years ago
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I don’t know how to solve this
g100num [7]
The two equations graphs intersect and the points where they are touching are belonging to both graphs therefore solutions for both equations.

(2) points (x,y) are
(-1,0) (-1)^2. +0^2=1; 1=1 ✔️
0=-1+1; 0=0✔️
(0, 1). (0)^2. +1^2=1; 1=1 ✔️
1=0+1; 1=1 ✔️
6 0
3 years ago
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