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3 years ago

14

A train traveled 210 miles and 3.5 hours to its first stop. It then continued on traveling another 130 miles in 2.5 hours. 2hat

was the average speed of the train for the entire Journey

1 answer:

SpyIntel [72]3 years ago

6 0

Answer:

56.7 mi/h.

Step-by-step explanation:

I took the test

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Akimi4 [234]

1/2, because 3/10 + 1/5 = 5/10. that means that the other part of 1 is 5/10 or 1/2

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3 years ago

Bryan drives at an average speed of 60 miles per hour.

riadik2000 [5.3K]

Answer:

180

Step-by-step explanation:

Multiply 60x3

and you will get 180miles

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3 years ago

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It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken if the desir

Ksju [112]

Answer:

We need a sample size of at least 75.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, we find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

The standard deviation is the square root of the variance. So:

$\sigma = \sqrt{484} = 22$

With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is

We need a sample size of at least n, in which n is found when M = 5. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$5 = 1.96*\frac{22}{\sqrt{n}}$

$5\sqrt{n} = 43.12$

$\sqrt{n} = \frac{43.12}{5}$

$\sqrt{n} = 8.624$

$(\sqrt{n})^{2} = (8.624)^{2}$

$n = 74.4$

We need a sample size of at least 75.

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3 years ago

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You have been given data about gas prices in 15 states. Comparing the two data sets below, what does the larger mean and median

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Comparing the two data sets shown below

<h3>What is standard deviation and variance?</h3>

Variance is the average squared deviations from the mean, while standard deviation is the square root of this number.

Both the mean and the median can be used to describe where the “center” of a dataset is located.

So, the mean of data in 2022 is more than mean of data in 2018.

It’s best to use the mean when the distribution of the data values is symmetrical and there are no clear outliers.

As the variance of 2022 more than in variance in 2018.

A high variance indicates that the data points are very spread out from the mean, and from one another.

As the standard deviation of 2022 more than in standard deviation in 2018.

The high standard deviation indicates data are more spread out.

The bigger the range, the more spread out the data.

Learn more about standard deviation, variance here:

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1 year ago

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